2mOm.dzNone of themm₂Im03* d₁, d₂ and ₂ are thejoint variablesFor the robot above, please determine K3 (the kinetic energy of Link #3)K3 = 1/2 (d ₂ ) ² + ²/2 (03) ²© K3 = ½ (d₁ ) ² + ½ (d₂ ) ² + ½ (03) ²K3 = ½ (di + d₂ ) ² + ³2 (03) ²K3 = ½ (d₁ + d₂ ) ² + ½ (03) ²m₂ = m₁ = m₂ = M₁₂ = 1 kgThe moment of inertia ofthe last link is 3 kg. m².The mass centers are locatedon the middle point of each link.

Answered: Image /qna-images/answer/d703c931-1a75-4705-942a-553f8f6baff2.jpg

2m m. di, d₂ and ₂ are the joint variables None of them m₂ = m₁ = m₂ = M₁₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link. For the robot above, please determine K3 (the kinetic energy of Link #3) =K₁ = K3 (d₂)² + ³ (6₂) ² © K3 = ¹½ (di)² + ½ (d₂)² + ¾(0)² K3 = ½ (d₁ + d₂ ) ² + ³ (0¹3) ² K3 = ½ (d₁ + d₂ ) ² + ½ (03) ²

2m m. di, d₂ and ₂ are the joint variables None of them m₂ = m₁ = m₂ = M₁₂ = 1 kg The moment of inertia of the last link is 3 kg. m². The mass centers are located on the middle point of each link. For the robot above, please determine K3 (the kinetic energy of Link #3) =K₁ = K3 (d₂)² + ³ (6₂) ² © K3 = ¹½ (di)² + ½ (d₂)² + ¾(0)² K3 = ½ (d₁ + d₂ ) ² + ³ (0¹3) ² K3 = ½ (d₁ + d₂ ) ² + ½ (03) ²

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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