1.5 mWAB = 4 rad/s0.5 m3) For the system given, the bar AB has an angularvelocity of waB = 4 rad/s. By use of vectornotation, determine the velocity of mass C, and0 = 30°the angular velocity of bar BC when 0 = 30°.

In the given mechanism the velocity of the mass C is equal to the velocity of the point B.

1.5 m AB = 4 rad/s 0.5 m/ 3) For the system given, the bar AB has an angular velocity of waR = 4 rad/s. By use of vector notation, determine the velocity of mass C, and \@ = 30° the angular velocity of bar BC when 0 = 30°. %3D

1.5 m AB = 4 rad/s 0.5 m/ 3) For the system given, the bar AB has an angular velocity of waR = 4 rad/s. By use of vector notation, determine the velocity of mass C, and \@ = 30° the angular velocity of bar BC when 0 = 30°. %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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1.5 m
WAB = 4 rad/s
0.5 m
3) For the system given, the bar AB has an angular
velocity of waB = 4 rad/s. By use of vector
notation, determine the velocity of mass C, and
0 = 30°
the angular velocity of bar BC when 0 = 30°.

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