29. During laboratory testing of an 8-inch aluminum-alloy rod with a cross sectional area of 0.32in², a tensile load of 40,000 lbs.is applied. If the croSs sectional area decreases to 0.3188in? and lengthens to 8.021 inches, what is the Modulus of Elasticity and Poisson's Ratio? E= 6/8 v =-e(lateral)/e(axial)
29. During laboratory testing of an 8-inch aluminum-alloy rod with a cross sectional area of 0.32in², a tensile load of 40,000 lbs.is applied. If the croSs sectional area decreases to 0.3188in? and lengthens to 8.021 inches, what is the Modulus of Elasticity and Poisson's Ratio? E= 6/8 v =-e(lateral)/e(axial)
Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN:9781337094740
Author:Segui, William T.
Publisher:Segui, William T.
Chapter1: Introduction
Section: Chapter Questions
Problem 1.5.5P: The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen...
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Step 1
Given:-
The length of the aluminum-alloy rod during testing = 8 inch
The cross-sectional area of the rod = 0.32 in2
The magnitude of the load applied = 40,000 lbs
The decreased cross-sectional area = 0.3188 in2
The changed length = 8.021 inches
To determine:-
The modulus of elasticity and Poisson's ratio
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