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A specimen of aluminum having a rectangular cross section 10.4 mm × 12.6 mm (0.4094 in. × 0.4961 in.) is pulled in tension with 35900 N (8071 lb;) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 x 106 psi). Calculate the resulting strain.

A specimen of aluminum having a rectangular cross section 10.4 mm × 12.6 mm (0.4094 in. × 0.4961 in.) is pulled in tension with 35900 N (8071 lb;) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 x 106 psi). Calculate the resulting strain.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A specimen of aluminum having a rectangular cross section 10.4 mm x 12.6 mm (0.4094 in. × 0.4961 in.) is pulled in tension with 35900 N (8071 Ib;) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 x 106 psi). Calculate the resulting strain.
Transcribed Image Text:A specimen of aluminum having a rectangular cross section 10.4 mm x 12.6 mm (0.4094 in. × 0.4961 in.) is pulled in tension with 35900 N (8071 Ib;) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 x 106 psi). Calculate the resulting strain.
Expert Solution
Step 1 Calculate the amount of Stress developed

So, stress can be defined as ;

σ = PA

P = Tension pull = 35900

A = 10.4 * 12.6 = 131.04 mm2

σ = 35900131.04 = 273.96 MPa

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