25 people were surveyed and 60% of them are in favor of to the used of street cameras issuing tickets a- Find the margin of error  E corresponds  to a  95% confidence level.         0.0169     0.0457     0.0265     0.0316

Q: A survey was conducted that asked 1017 people how many books they had read in the past year. Results…

A: In the problem, the following are given:xˉ=12.8; The mean number of books the respondents read in…

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: In a survey of 2865 ​adults, 1413 say they have started paying bills online in the last year.…

A:

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: In a survey of 4026 ​adults, 708 oppose allowing transgender students to use the bathrooms of the…

A: Given:  n=4026 x=708

Q: A survey was constructed that asked 1017 people how many books they had read in the past year.…

A: The following information has been given: The sample size is n=1017. The sample mean is x¯=10.5. The…

Q: A sample of 100 homes in city A and 100 homes in City B was taken to estimate the proportion of the…

A: Given that, A sample of 100 homes in city A and 100 homes in city B were taken to estimate the…

Q: A sample of 200 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A: Given:

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: a survey of 3447 adults, 1477 say they have started paying bills online in the last year.…

A:

Q: A 90% confidence interval for the mean proportion of airline reservations being canceled on the day…

A: Solution: From the given information, a 90% confidence interval for the mean proportion of airline…

Q: What value should be reported as the mean?

A: Given, Values 4.63 4.58 4.82 4.31 4.67 4.6

Q: A survey was conducted that asked 1011 people how many books they had read in the past year. Results…

A:

Q: In a survey of 4008 ​adults, 728 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a survey of 4052 ​adults, 723 oppose allowing transgender students to use the bathrooms of the…

A: It is given that x = 723 and n= 4,052.

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: A survey of 45,535 adults showed that 20,901 were very concerned abut climate change. What is the…

A:

Q: A large container contains colored beads. A simple random sample of beads yielded 107 red beads and…

A:

Q: In a survey of 26582658 ​adults, 14961496 say they have started paying bills online in the last…

A: The objective of this question is to construct a 99% confidence interval for the population…

Q: 67% out of 150 pupils from school A passed an exam; 62% of 120 pupils at school B passed. Estimate…

A: Given : n1 = 150 n2 = 120 confidence level,c=0.9

Q: a research poll institute asked respondents if they fet vulnerable to identify theft. in the poll,…

A: Given Data: n=1002 x=595 α=0.05   Calculating the sample proportion p⏜=xn=5951002=0.5938 As n is…

Q: A survey of 45,535 adults showed that 20,901 were very concerned abut climate change. What is the…

A: It is given asFavourable cases, x = 20901Sample size, n = 45535Confidence level = 99%

Q: A survey was conducted that asked 1017 people how many books they had read in the past year. Results…

A: The provided information is  x¯=12.2s=16.6n=1017α=0.10The degrees of freedom is…

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and…

A: The objective of this question is to find the 95% confidence interval for the mean weight of all…

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: In a survey of 3983 ​adults, 747 oppose allowing transgender students to use the bathrooms of the…

A:

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: A survey found that 39 of 66 people who don't drink coffee often have trouble sleeping and 44 of 88…

A: Solution: Let X1 be the number of noncoffee drinkers who have trouble sleeping, n1 be the sample…

Q: In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2693 ​adults, 1495 say they have started paying bills online in the last…

Q: In a random sample of 144 observations, the sample proportion is 0.90. Construct a 95% confidence…

A: given data sample size (n) = 144P^ = 0.9095% ci p.

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the​ poll,…

A:

Q: A sample of 421 adults showed that 239 of them are connected to the Internet from home.  Construct…

A: From the provided information, Sample size (n) = 421 From which 239 are connected to the Internet…

Q: A sociologist develops a test to measure attitudes about public transportation, and 27 randomly…

A: Given,sample size(n)=27sample mean(x¯)=76.2standard deviation(s)=21.4degrees of…

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…

Q: A survey was conducted that asked 1012 people how many books they had read in the past year. Results…

A: GivenMean(x)=13.1standard deviation(s)=16.6sample size(n)=1012confidence…

Q: Suppose a marketing company computed a 96% confidence interval for the true proportion of customers…

A: The objective of the question is to understand the meaning of the given 96% confidence interval for…

Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: 90% confidence interval for the mean of airline reservations being canceled on the day of the flight…

A: Given 90% confidence interval is (2.68,9.42)   Lower limit=2.68 Upper limit=9.42 Point estimate p=?

Q: A random sample of newborn baby boys were weighed. x = 6.7 lb s = 1.3 lb n = 79 1. What is the point…

A:

Q: n a survey of 3196 adults, 1405 say they have started paying bills online in the last year.…

A: Given data, n=3196 x=1405 p=x/n=1405/3196 =0.4396 z-value at 99% confidence is Zc=2.576

Q: ence interval for the mean price. 7. A random sample of 480 Oklahoma parents with school-aged…

A: