**Transcription for Educational Website:** --- **Problem Statement:** A random sample of 480 Oklahoma parents with school-aged children showed that 276 had children doing at least some virtual learning. Find a 97.8% confidence interval for the proportion of all Oklahoma parents who have children doing some form of virtual learning. **Notes:** - Sample size (\( n \)) = 480 - Number of parents with children in virtual learning = 276 - Confidence level = 97.8% **Calculation Details:** - Proportion (\( \hat{p} \)) = \( \frac{276}{480} = 0.575 \) - Confidence interval = 97.8% --- For educational purposes, a teacher may guide students through calculating the confidence interval using the above data and notes.

MATLAB: An Introduction with Applications
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ISBN:9781119256830
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**Transcription for Educational Website:**

---

**Problem Statement:**

A random sample of 480 Oklahoma parents with school-aged children showed that 276 had children doing at least some virtual learning. Find a 97.8% confidence interval for the proportion of all Oklahoma parents who have children doing some form of virtual learning.

**Notes:**

- Sample size (\( n \)) = 480
- Number of parents with children in virtual learning = 276
- Confidence level = 97.8%

**Calculation Details:**

- Proportion (\( \hat{p} \)) = \( \frac{276}{480} = 0.575 \)
- Confidence interval = 97.8%

---

For educational purposes, a teacher may guide students through calculating the confidence interval using the above data and notes.
Transcribed Image Text:**Transcription for Educational Website:** --- **Problem Statement:** A random sample of 480 Oklahoma parents with school-aged children showed that 276 had children doing at least some virtual learning. Find a 97.8% confidence interval for the proportion of all Oklahoma parents who have children doing some form of virtual learning. **Notes:** - Sample size (\( n \)) = 480 - Number of parents with children in virtual learning = 276 - Confidence level = 97.8% **Calculation Details:** - Proportion (\( \hat{p} \)) = \( \frac{276}{480} = 0.575 \) - Confidence interval = 97.8% --- For educational purposes, a teacher may guide students through calculating the confidence interval using the above data and notes.
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