24. For figure 3; Expression for the resistor current Ir valid for all time, is:2 kN12 mHFigure 34 Vt = 030 kM * 2 pF-7.823×1010t-0.511×1010tα) μΑа. 2.437(eb. 80ес. 161.3еd. -2(e2 -2 e) µA50,000t – 20e-200,000te 3.063×106t – 36 34e13.6×106tHAe. None of these

Answered: Image /qna-images/answer/1d93c0a4-d8c9-4f60-b3ed-b4d8867864ff.jpg

24. For figure 3; Expression for the resistor current İr valid for all time, is: Figure 3 12 mH rell 2 kN 4 V t= 0 iR 30 kN 2 pF a. 2.437(e7,823×1010t – e 0.511×1010t HA 50,000t – 20e¯200,000t µA b. 80e* c. 161.3e¯3.063×1061 – 36.34e13.6×106t, d. -2(e2 -2 e*) µA 1/2 e. None of these

24. For figure 3; Expression for the resistor current İr valid for all time, is: Figure 3 12 mH rell 2 kN 4 V t= 0 iR 30 kN 2 pF a. 2.437(e7,823×1010t – e 0.511×1010t HA 50,000t – 20e¯200,000t µA b. 80e* c. 161.3e¯3.063×1061 – 36.34e13.6×106t, d. -2(e2 -2 e*) µA 1/2 e. None of these

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

100%

24. For figure 3; Expression for the resistor current Ir valid for all time, is:
2 kN
12 mH
Figure 3
4 V
t = 0
30 kM * 2 pF
-7.823×1010t-0.511×1010t
α) μΑ
а. 2.437(e
b. 80е
с. 161.3е
d. -2(e2 -2 e) µA
50,000t – 20e-200,000t
e 3.063×106t – 36 34e13.6×106t
HA
e. None of these

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