current of 1 = -6 + 8 12 sin (wt + 30) is passed through a cen I

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...
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A current of i = -6 + 8 √2 sin (wt + 30) is passed through a centre zero PMMC meter and a moving iron meter. The two meters will read:
Transcribed Image Text:A current of i = -6 + 8 √2 sin (wt + 30) is passed through a centre zero PMMC meter and a moving iron meter. The two meters will read:
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