Assume that the currents I1, I2, and I are in the directions indicated by the arrows in the figure redrawn below. (Enter your answers to at least four significant figures.) 12.0 V R₁ or Solving for I₁ gives a Applying Kirchhoff's junction rule at a gives 13 = 1₁ + 1₂. [1] Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields 3.00 V 18.0 V Im R3 -3.00 V-R₂13-R₁1₁ + 12.0 V = 0. 0 0 1₁ = The correct answer is not zero. V R₁ v) - (R²) 13, X 1₁ = The correct answer is not zero. A A)-(0 The correct answer is not zero. 0.)13. [2] X

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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27.15

=
Find the potential difference across each resistor in the figure below. (R₁ = 5.25 , R₂
12.0 V
R₁
3.00 V
I
R₂.
RA
www
R3
18.0 V
3.900, R3 = 2.700, R4
=
1.70 (2)
Transcribed Image Text:= Find the potential difference across each resistor in the figure below. (R₁ = 5.25 , R₂ 12.0 V R₁ 3.00 V I R₂. RA www R3 18.0 V 3.900, R3 = 2.700, R4 = 1.70 (2)
Assume that the currents I₁, I2, and I are in the directions indicated by the arrows in the figure redrawn below. (Enter your answers to at
least four significant figures.)
1₁ a 12₂
or
12.0 V
Solving for I₁ gives
1₁
R₁
=
3.00 V 18.0 V
Applying Kirchhoff's junction
rule at a gives
13 = 1₁ + 1₂.
[1]
Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields
-3.00 V - R₂13 − R₁I₁ + 12.0 V = 0.
13
R₂ R₁
R3
0
X
The correct answer is not zero. V
R₁
X
I₁ = The correct answer is not zero. A
v) - (²²) ¹₂
(R2)131
0
The correct answer is not zero. 13. [2]
X
Transcribed Image Text:Assume that the currents I₁, I2, and I are in the directions indicated by the arrows in the figure redrawn below. (Enter your answers to at least four significant figures.) 1₁ a 12₂ or 12.0 V Solving for I₁ gives 1₁ R₁ = 3.00 V 18.0 V Applying Kirchhoff's junction rule at a gives 13 = 1₁ + 1₂. [1] Using Kirchhoff's loop rule starting at point a and going clockwise around the leftmost loop yields -3.00 V - R₂13 − R₁I₁ + 12.0 V = 0. 13 R₂ R₁ R3 0 X The correct answer is not zero. V R₁ X I₁ = The correct answer is not zero. A v) - (²²) ¹₂ (R2)131 0 The correct answer is not zero. 13. [2] X
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