Given. A beam 24 in. wide x 26 in. deep as shown in Fig. 4.35. The beam is partof the lateral resisting system that consists of an intermediate reinforced concrete momentframe.Ultimate design values are as follows:Support moment -M= 376 kip-ft-M= 188 kip-ft10-030'-0"10-010-0Half Trib. Areafor 84-8424"W x 26*DMidspan moment +M = 157 kip-ft3012Nominal moments (= 1) are as follows:At supports: -M₁ = 418 kip-ft-Mr = 209 kip-ft27.50 ft20-0Clear span= 30-Shear force due to seismic = 50 kipsShear force due to gravity loads = 63 kipsf = 4000 psi, f, = 60,000 psiRequired. Design and schematic of reinforcement for beam B4 using the provi-sions of ACI318-99,

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24 in. Vide x 26 in. deep Fig. beam is part of the lateral resisting system that consists of an intermediate reinforced concrete moment frame. Ultimate design values are as follows: Support moment -M₁= 376 kip-ft -M= 188 kip-ft Nominal moments (= 1) are as follows: At supports: -M₁ = 418 kip-ft -M=209 kip-ft

24 in. Vide x 26 in. deep Fig. beam is part of the lateral resisting system that consists of an intermediate reinforced concrete moment frame. Ultimate design values are as follows: Support moment -M₁= 376 kip-ft -M= 188 kip-ft Nominal moments (= 1) are as follows: At supports: -M₁ = 418 kip-ft -M=209 kip-ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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