The wood beam supports loads of w = 450 lb/ft and P = 1100 lb on span lengths of LAB = 9.4 ft, LBC = 4.7 ft, and LCD= 4.7 ft. The beam cross section has dimensions of b1 = 1.7 in., d1 = 5.1 in., b2 = 5.4 in., and d2 = 14.05 in. Determine the magnitude and location of: (a) the maximum horizontal shear stress in the beam. (b) the maximum tensile bending stress in the beam. d1 B C LaB LBC LCD b| b2 Answer: (a) Tmax = psi (b) Omax = psi
The wood beam supports loads of w = 450 lb/ft and P = 1100 lb on span lengths of LAB = 9.4 ft, LBC = 4.7 ft, and LCD= 4.7 ft. The beam cross section has dimensions of b1 = 1.7 in., d1 = 5.1 in., b2 = 5.4 in., and d2 = 14.05 in. Determine the magnitude and location of: (a) the maximum horizontal shear stress in the beam. (b) the maximum tensile bending stress in the beam. d1 B C LaB LBC LCD b| b2 Answer: (a) Tmax = psi (b) Omax = psi
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![The wood beam supports loads of w = 450 lb/ft and P = 1100 lb on span lengths of LAB = 9.4 ft, LBC = 4.7 ft, and LCD= 4.7 ft. The beam
cross section has dimensions of b1 = 1.7 in., d1 = 5.1 in., b2 = 5.4 in., and d2 = 14.05 in. Determine the magnitude and location of:
(a) the maximum horizontal shear stress in the beam.
(b) the maximum tensile bending stress in the beam.
P
di
d2
B
C
D
LAB
LBC
LCD
|b|
b2
|b1
Answer:
(a) Tmax =
psi
(b) Omax =
psi](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff4b4f8be-8a22-47b5-ba29-6d91e6065e9e%2Febd20475-b6c7-4ba1-bd97-c11dff3fb144%2Fuj0e2l_processed.png&w=3840&q=75)
Transcribed Image Text:The wood beam supports loads of w = 450 lb/ft and P = 1100 lb on span lengths of LAB = 9.4 ft, LBC = 4.7 ft, and LCD= 4.7 ft. The beam
cross section has dimensions of b1 = 1.7 in., d1 = 5.1 in., b2 = 5.4 in., and d2 = 14.05 in. Determine the magnitude and location of:
(a) the maximum horizontal shear stress in the beam.
(b) the maximum tensile bending stress in the beam.
P
di
d2
B
C
D
LAB
LBC
LCD
|b|
b2
|b1
Answer:
(a) Tmax =
psi
(b) Omax =
psi
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