23°C, calculate the gas constant, R. (assume: PH202 Lab Section 4) Hydrogen peroxide decomposes spontaneously slowly to form water and oxygen gas according to the following chemical equation: 2 H2O2 () → 2 H,O (1)+ O2 (g) This decomposition can be sped up with the addition of a catalyst. If 198 mL of H2O2 decomposes and the amount of oxygen gas collected over water is 72.5 L at 756 mmHg and : 1.0으) mL %3D

Introduction to Chemical Engineering Thermodynamics
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ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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23°C, calculate the gas constant, R. (assume: PH202
Lab Section
4) Hydrogen peroxide decomposes spontaneously slowly to form water and oxygen gas
according to the following chemical equation:
2 H2O2 () → 2 H,O (1)+ O2 (g)
This decomposition can be sped up with the addition of a catalyst. If 198 mL of H2O2
decomposes and the amount of oxygen gas collected over water is 72.5 L at 756 mmHg and
: 1.0으)
mL
%3D
Transcribed Image Text:23°C, calculate the gas constant, R. (assume: PH202 Lab Section 4) Hydrogen peroxide decomposes spontaneously slowly to form water and oxygen gas according to the following chemical equation: 2 H2O2 () → 2 H,O (1)+ O2 (g) This decomposition can be sped up with the addition of a catalyst. If 198 mL of H2O2 decomposes and the amount of oxygen gas collected over water is 72.5 L at 756 mmHg and : 1.0으) mL %3D
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