222) data 250 Assume 225 KVA KVA 13.8/0.48 KV y- A short-circuit Test Dara (aon Primary) Vesc = 250V a A) Impedance bhe Transformer BP₁₂ - sc = 2500 W transformer with the following Ratings Load Dara K√ load = 0.504 KA of Primary Ipse = 10.46A PE=0.86 lagging the transformer as referred to side on B secondary current referred to the primary the primary dLine voltage D) Voltage regulation as percentage E) Transformer efficiency as Percentage

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.9P
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Please sir solve this question, electric machines

Q2) Assume a transformer with the following
Trans former
Ratings
data
13.8/0.48 KV
у- Д
short-circuit Test Dara (aon Primary)
Vesc = 250V
250
KVA
BB- sc = 2500 W
225KVA
A) Impedance
bhe
Load
of
K√ load =
Dara
PE=0.86 lagging
the transformer as referred to
on
0.504 KA
Ips<= 10.46A
Primary side
B) secondary current referred to the primary.
the primary
dLine voltage
D) Voltage
regulation as percentage
E) Transformer efficiency as Percentage
Transcribed Image Text:Q2) Assume a transformer with the following Trans former Ratings data 13.8/0.48 KV у- Д short-circuit Test Dara (aon Primary) Vesc = 250V 250 KVA BB- sc = 2500 W 225KVA A) Impedance bhe Load of K√ load = Dara PE=0.86 lagging the transformer as referred to on 0.504 KA Ips<= 10.46A Primary side B) secondary current referred to the primary. the primary dLine voltage D) Voltage regulation as percentage E) Transformer efficiency as Percentage
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