22. Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH3CH₂Br 2) NaNH, 3) (CH3)3CBr A) The alkynide anion is not a strong enough nucleophile to react with 1- bromopropane in step 1. B) Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2. HCEC: CH3CH₂C=CC(CH3)3 C) The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide. D) Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown. E) Reaction with sodium amide will result in formation of a primary alkyne.

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22. Which of the following best explains why the synthetic route shown below would
be unsuccessful?
1) CH3CH₂Br
2) NaNH,
3) (CH3)3CBr
A) The alkynide anion is not a strong enough nucleophile to react with 1-
bromopropane in step 1.
B) Sodium amide is not a strong enough base to deprotonate the terminal
alkyne in step 2.
HC=C:
CH₂CH₂C=CC(CH3)3
C) The alkynide anion formed by reaction with sodium amide will facilitate an E2
(rather than SN2) reaction with t-butyl bromide.
D) Both substitution reactions will occur on the same end of the alkyne, making
a product different than the one shown.
E) Reaction with sodium amide will result in formation of a primary alkyne.
Transcribed Image Text:22. Which of the following best explains why the synthetic route shown below would be unsuccessful? 1) CH3CH₂Br 2) NaNH, 3) (CH3)3CBr A) The alkynide anion is not a strong enough nucleophile to react with 1- bromopropane in step 1. B) Sodium amide is not a strong enough base to deprotonate the terminal alkyne in step 2. HC=C: CH₂CH₂C=CC(CH3)3 C) The alkynide anion formed by reaction with sodium amide will facilitate an E2 (rather than SN2) reaction with t-butyl bromide. D) Both substitution reactions will occur on the same end of the alkyne, making a product different than the one shown. E) Reaction with sodium amide will result in formation of a primary alkyne.
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