The synthesis of acid orange 7 is shown below. Please answer the following questions. 8 7. 1 2 OH NH3 N2 3 5 4 SO3 Na 1) NażCO3 2) NaNO2, HCI A ß-naphthol LOH 1 Step 1 2 Step 2 Acid orange 7 In step 2, please choose all that explain the selectivity of this electrophilic aromatic substation reaction Select one or more: O A. Because hydroxyl group (-OH) is a ortho/para director, compound 2 selectively adds to the 1 position of B-naphthol. O B. Because hydroxyl group (-OH) is a meta director, compound 2 selectively adds to the 1 position of B-naphthol O C. Because hydroxyl group (-OH) is electron donation group, compound 2 selectively adds to the right ring of B-naphthol O D. Because hydroxyl group (-OH) is electron withdrawing group, compound 2 selectively adds to the right ring of B-naphthol

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The synthesis of acid orange 7 is shown below. Please answer the following questions.
8 1
2 OH
N2
SO3
NH3
SO3 Na
4
1) Na2CO3
A
EOS
B-naphthol
2) NaNO2, HCI
HO
Step 1
2
Step 2
3
Acid orange 7
In step 2, please choose all that explain the selectivity of this electrophilic aromatic
substation reaction
Select one or more:
O A. Because hydroxyl group (-OH) is a ortho/para director, compound 2 selectively
adds to the 1 position of B-naphthol.
O B. Because hydroxyl group (-OH) is a meta director, compound 2 selectively adds
to the 1 position of B-naphthol
O C. Because hydroxyl group (-OH) is electron donation group, compound 2
selectively adds to the right ring of B-naphthol
O D. Because hydroxyl group (-OH) is electron withdrawing group, compound 2
selectively adds to the right ring of B-naphthol
Transcribed Image Text:The synthesis of acid orange 7 is shown below. Please answer the following questions. 8 1 2 OH N2 SO3 NH3 SO3 Na 4 1) Na2CO3 A EOS B-naphthol 2) NaNO2, HCI HO Step 1 2 Step 2 3 Acid orange 7 In step 2, please choose all that explain the selectivity of this electrophilic aromatic substation reaction Select one or more: O A. Because hydroxyl group (-OH) is a ortho/para director, compound 2 selectively adds to the 1 position of B-naphthol. O B. Because hydroxyl group (-OH) is a meta director, compound 2 selectively adds to the 1 position of B-naphthol O C. Because hydroxyl group (-OH) is electron donation group, compound 2 selectively adds to the right ring of B-naphthol O D. Because hydroxyl group (-OH) is electron withdrawing group, compound 2 selectively adds to the right ring of B-naphthol
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