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20) Two AC generators A and B are in Parallel. Each generator has an emf of 1000V per phase and in phase, the phase impedance are ZA = 0.1+j2 ohms, ZB = 0.2+j3.2 ohms respectively. If the common load has an impedance of (2+j1) ohms per phase, solve the voltage per phase at the load

20) Two AC generators A and B are in Parallel. Each generator has an emf of 1000V per phase and in phase, the phase impedance are ZA = 0.1+j2 ohms, ZB = 0.2+j3.2 ohms respectively. If the common load has an impedance of (2+j1) ohms per phase, solve the voltage per phase at the load

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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20) Two AC generators A and B are in Parallel. Each generator has an emf of 1000V per phase and in phase, the phase impedance are ZA = 0.1+j2 ohms, ZB = 0.2+j3.2 ohms respectively. If the common load has an impedance of (2+j1) ohms per phase, solve the voltage per phase at the load
Transcribed Image Text:20) Two AC generators A and B are in Parallel. Each generator has an emf of 1000V per phase and in phase, the phase impedance are ZA = 0.1+j2 ohms, ZB = 0.2+j3.2 ohms respectively. If the common load has an impedance of (2+j1) ohms per phase, solve the voltage per phase at the load
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