20 n block is placed on an inclined plane and connected to a 10 n hanging block by a cord that passes over a frictionless pulley. the coefficient of kinetic friction between block and plane is 1/3. find one value of angle ꝋ so that the hanging block will move downward at constant velocity once set in motion. Note: You don’t have to answer the whole question. Please just explain to us how to get the 31 number in the picture. Thank you.

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a 20 n block is placed on an inclined plane and connected to a 10 n hanging block by a cord that passes over a frictionless pulley. the coefficient of kinetic friction between block and plane is 1/3. find one value of angle ꝋ so that the hanging block will move downward at constant velocity once set in motion. Note: You don’t have to answer the whole question. Please just explain to us how to get the 31 number in the picture. Thank you.
Step. O bolvi ng the
equation (2 to get the angle (0).
1o -
20 Sino
20 Cas o =
Sin o
Cas e
3 Sina - Cas O
2
+ Cas o =
3 1- Cas?0
- On squaring bathaide : -
1 + Casto + 3 Cas 0
9 + 9 Cas ?0 = o
9 + 4 Cas?o + 12 Cas 0 - 36 + 36 Cai?o = o
(40 Cas'o + 12 Cas o - 27 - 0
- applying nridhaxechazeya 'a tormula
Cas 0
3( 131 -1)
20
Cas 9 = 3(5.57 - 1)
3 (4.57)
Cas 8 =
0.69
20
20
%3D
[0 - 46-30 ]
Hence, the angle shauld be 46.36
meve the hanging blo us
to
downwand with constand- velocity.
Transcribed Image Text:Step. O bolvi ng the equation (2 to get the angle (0). 1o - 20 Sino 20 Cas o = Sin o Cas e 3 Sina - Cas O 2 + Cas o = 3 1- Cas?0 - On squaring bathaide : - 1 + Casto + 3 Cas 0 9 + 9 Cas ?0 = o 9 + 4 Cas?o + 12 Cas 0 - 36 + 36 Cai?o = o (40 Cas'o + 12 Cas o - 27 - 0 - applying nridhaxechazeya 'a tormula Cas 0 3( 131 -1) 20 Cas 9 = 3(5.57 - 1) 3 (4.57) Cas 8 = 0.69 20 20 %3D [0 - 46-30 ] Hence, the angle shauld be 46.36 meve the hanging blo us to downwand with constand- velocity.
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