Two packages at UPS start sliding down the 20.0° ramp shown in (Figure 1). Package A has a mass of 2.00 kg and a coefficient of kinetic friction of 0.500. Package B has a mass of 10.0 kg and a coefficient of kinetic friction of 0.150. For help with math skills, you may want to review: Vector Components B A 2.00 m 20.0° How long does it take package A to reach the bottom? Express your answer with the appropriate units. ► View Available Hint(s) At = |µĂ Value Units ?
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- I need help in this problem pleaseThree blocks are arranged as shown in the diagram above. Assume all pulleys and strings are massless and frictionless. There is kinetic friction between blocks 2 and 3 and the planes underneath them. Block 2 is sliding to the right. Block 1 has a mass of m1 = 1.4 kg and it hangs from a string that runs over a pulley. The other end of that string is connected to Block 2 which has a mass of m2 =2.4 kg, and slides over a horizontal plane. On the other side of Block 2 is a different string that runs over another pulley and then connects to Block 3 which has a mass of mass m3 = 4.4 kg, and slides over a plane that is inclined at an angle of θ = 32 degrees away from vertical (see the diagram, above). Blocks 2 and 3 both slide over their surfaces with a coefficient of kinetic friction of μ K = 0.37. Block 2 is moving to the right while block 3 is moving down and to the right. Let g =9.8 meters per second squared. Calculate the acceleration of Block B in units of meters per second squared.…A block of mass m1 = 38.7 kg on a horizontal surface is connected to a mass m, = 21.9 kg that hangs vertically as shown in the figure below. The two blocks are connected by a string of negligible mass passing over a frictionless pulley. Assume that the horizontal surface is smooth. m, m. (a) What is the acceleration (in m/s2) of the hanging mass? (Enter the magnitude only.) m/s2 (b) Determine the tension (in N) in the cord. (Enter the magnitude only.) N
- Please solve for T1. I have solved several times, but I think I am missing how to split the tension force into X/Y vector components. Thanks!One straightforward way to measure the coefficients of friction between a box and a wooden surface is illustrated in (Figure 1). The sheet of wood can be raised by pivoting it about one edge. It is first raised to an angle θ1 (which is measured) for which the box just begins to slide downward. The sheet is then immediately lowered to an angle θ2 (which is also measured) for which the box slides with constant speed down the sheet. Part A) Apply Newton’s second law to the box to find the coefficient of static friction between it and the wooden sheet. Express your answer in terms of some or all of the variables θ1 and θ2. Part B) Apply Newton’s second law to the box to find the coefficient of kinetic friction between it and the wooden sheet. Express your answer in terms of some or all of the variables θ1 and θ2.Two weights are hanging from the ceiling of an elevator as shown in (Figure 1). Find the tension in cable A when the elevator is not moving. Express your answer in newtons. Find the tension in cable B when the elevator is not moving. Express your answer in newtons. Find the tension in cable B when the elevator is accelerating downward at 1.4 m/s2. Express your answer in newtons. Find the tension in cable A when the elevator is accelerating downward at 1.4 m/s2. Express your answer in newtons.
- A force acts at the origin of a coordinate system in a direction defined by the angles a = 113.2° and Øß = 78.4°. Knowing that the z component of the force is -35 lb, determine (a) the angle y, (b) the other components and the magnitude of the force. At the end of your solution, draw a 3D sketch showing F and its components - similar to the first 3D example we did in class. (Hint: for this problem only you do not need to start your solution with a FBD. Do not include a sketch in the “Problem" section as you were not given a picture.) (Partial answer hint: F = 39.0 lb. Note: this partial answer hint is like checking the back of the book. You consider this as "given" information.) %3D may notJuan pushes a lawn mower with a force of 75 N holding the handle in such a way that it makes an angle of 60.0 ° with the horizontal. Remember to make the diagram and identify the vectors. 1. What are the horizontal and vertical components of the force? 2. The handle is lowered so that it makes an angle of 30.0o with the horizontal. What are the horizontal and vertical components of the force?Find the Resultant of the following Forces by Component Method. F₁ = 12 N. West F₂= 24 N, 30° North of West F3 = 15 N, 75° South of West F₁ = 28 N, 50° South of East Draw the initial and final graphical representation that will illustrate R and show your solution. Find the Resultant of the following Forces by Component Method. F₁ = 12 N. West F₂= 24 N, 30° North of West F3 = 15 N, 75° South of West F₁ = 28 N, 50° South of East Draw the initial and final graphical representation that will illustrate R and show your solution.
- A cylinder is given a push and then rolls up an inclined plane. If the origin is the starting point, sketch the position, velocity,and acceleration of the cylinder vs. time as it goes up and then down the plane.Question 2: You are a structural engineer working for a bridge design company. design a gusset plate connection for a bridge truss support. You need to find the resultant force and its direction. Solve all parts step-by step, show your calculations and answers in the box. For vector components, include the sign to indicate direction, +ve if the component points in the +ve direction of the axis. Express final answers using vector component notation x = and y are the scalar component values and i and j are the unit vectors pointing along the +ve x and y axes, respectively. Your manager asked you to xi + vj where x y F2 = 50 kN F1 = 25 kN F3 = 30 kN X 0.8 m a) (LO2) Find the components of force F1. y F1 = 25 kN F1y Fıx Answer: tu poc