20 in. 28 in. -75 in.- c 12 in. E 12 in. 12 in. 20 in. 18 in. 24 in. 4500 lb н 22 in. 10 in.
Q: A meter stick has a mass of 0.24 kg and balances (by itself) at its geometric center. When a small…
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Q: For two existing torques, what third force at a given distance from the pivot will balance them?…
A: Given: m1 = 100 gm = 0.1 kgx1 = 20 cm = 0.2 cmm2 = 250 gm = 0.25 kgx2 = 80 cm = 0.8 mx3 = 60 cm…
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A: radius = 50 cm = 0.5 m mass = 1 kg mass of object = 2 kg Tension = M (g-a) = 2 (9.8- a) = 19.6 - 2a…
Q: Find τp,w, the torque about the pivot due to the weight w of the smaller child on the seesaw.…
A: HERE WE NEED TO FIND THE TORQUE ABOUT PIVOT torque(τ)=r×Fτ=rFsinθr distance from hingeF is forceθ is…
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A: the values provided in the question are as follows- mass = m1 and m2 friction= u for calculating…
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A: Note: as per guidelines only one question should be answered, so kindly post the remaining question…
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Q: A thin- walled cylinder of radius 50 cm, mass 1.0 kg, is mounted on a frictionless, horizontal axle…
A: radius = 50 cm mass = 1 kg mass of object = 2 kg using , Tension = M (g-a) T = 2(9.8-a)T = 19.6 - 2a…
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Q: In the figure below, the cg of the pole held by the pole vaulter is 2.54 m from the left hand, and…
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The motion of the bucket of the front-end loader shown is controlled by two arms and a linkage that are pin-connected at D. The arms are located symmetrically with respect to the central vertical and longitudinal plane of the loader; one arm AFJ and its control cylinder EF are shown. The single linkage GHDB and its control cylinder BC are located in the plane of symmetry. For the position and loading shown, determine the force exerted (a) by cylinder BC, (b) by cylinder EF.


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- In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as shown in the figure here. One cord makes the angle 8 = 34.4 with the vertical; the other makes the angle o = 55.6 with the vertical. If the length L of the bar is 3.4 m, compute the distancex from the left end of the bar to its center of mass. comFor two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3A block with mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 11.1 kg and moment of inertia 0.500 kg - m? with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.300 m from that axis. Part A What is the acceleration of the block down the plane? Express your answer in meters per second squared. ? a = 1.45 m/s? Figure 1 of 1 Part B What is the tension in the string? Express your answer in newtons. 5.00 kg ? T = 11.6 N 36.9 國
- The drawing below shows two forces acting on a rigid beam. The blue dot is the center of mass of the beam. The forces (red arrows) are equal in magnitude. Consider the net force on the beam and net torque about its center. Which of the following statements are true? Check ALL that apply. The net force is zero. The net force is not zero. The net torque is zero. O The net torque is not zero.Hand written and clean answerFor two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3
- M, R m1 m2 Refer to the figure above for this problem. A wooden bldck of mass m, = 3.2 kg and a hollow block of mass m2 = 8.7 kg are connected by a rope which runs over a friction-less pulley. Assume that the pulley is a solid iron disc with a radius R = 0.3 m and mass M = 5.1 kg. The ramp is wedge- shaped and makes an angle of 0=36°. The coefficient of kinetic friction is 0.29 for both blocks and the wedgeshaped incline. (a) Draw force diagrams of both blocks and of the pulley. (b) Determine the acceleration of the two blocks. (c) Determine the tensions in the string on both sides of the pulley.You are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. In all cases, assume that m1>m2 and that counterclockwise is considered the positive rotational direction.This time, the swing bar of mass mbarmbar is pivoted at a different point, as shown in the figure.Find the magnitude of the angular acceleration α of the swing bar. Be sure to use the absolute value function in your answer, since no comparison of m1m2 mbar has been made. Express your answer in terms of some or all of the quantities m1 m2 mbar and g abs(). For instance, enter abs(x*y) for |xy|.The swimmer in the figure below propels himself forward by exerting a 138 N backward force on the water with his hand. He experiences a forward reaction force F of magnitude 138 N. Find the magnitude and direction of the torque exerted on the arm by F about an axis through point O. (Let d = 43.0 cm.) magnitude