A block with mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 11.1 kg and moment of inertia 0.500 kg - m? with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.300 m from that axis. Part A What is the acceleration of the block down the plane? Express your answer in meters per second squared. ? a = m/s? Part B igure < 1 of 1 What is the tension in the string? Express your answer in newtons. 5.00 kg T = N 36.9

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Chapter1: Units, Trigonometry. And Vectors
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A block with mass m = 5.00 kg slides down a surface
inclined 36.9° to the horizontal (Figure 1). The coefficient of
kinetic friction is 0.27. A string attached to the block is
wrapped around a flywheel on a fixed axis at O. The flywheel
has mass 11.1 kg and moment of inertia 0.500 kg - m2 with
respect to the axis of rotation. The string pulls without
slipping at a perpendicular distance of 0.300 m from that
axis.
Part A
What is the acceleration of the block down the plane?
Express your answer in meters per second squared.
?
a =
m/s?
Part B
Figure
< 1 of 1>
What is the tension in the string?
Express your answer in newtons.
5.00 kg
T =
N
36.9°
Transcribed Image Text:A block with mass m = 5.00 kg slides down a surface inclined 36.9° to the horizontal (Figure 1). The coefficient of kinetic friction is 0.27. A string attached to the block is wrapped around a flywheel on a fixed axis at O. The flywheel has mass 11.1 kg and moment of inertia 0.500 kg - m2 with respect to the axis of rotation. The string pulls without slipping at a perpendicular distance of 0.300 m from that axis. Part A What is the acceleration of the block down the plane? Express your answer in meters per second squared. ? a = m/s? Part B Figure < 1 of 1> What is the tension in the string? Express your answer in newtons. 5.00 kg T = N 36.9°
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