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2.2kQ 4700 1kQ 3300 IL RL = 4.55kQ -6 V 680Ω -15 V В 1) Determine the value of the load resistor that will dissipate the most power, when connected to the Circuit. (Hint: Use the Thevenin Equivalent circuit). 2) Calculate the current flowing through the load resistor, the voltage across the load resistor, and how much power it dissipates.

2.2kQ 4700 1kQ 3300 IL RL = 4.55kQ -6 V 680Ω -15 V В 1) Determine the value of the load resistor that will dissipate the most power, when connected to the Circuit. (Hint: Use the Thevenin Equivalent circuit). 2) Calculate the current flowing through the load resistor, the voltage across the load resistor, and how much power it dissipates.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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C. 2.2kQ 4702 1kQ 3302 RL = 4.55k2 6802 =6 V 15 V В 1) Determine the value of the load resistor that will dissipate the most power, when connected to the Circuit. (Hint: Use the Thevenin Equivalent circuit). 2) Calculate the current flowing through the load resistor, the voltage across the load resistor, and how much power it dissipates. 3) Using the Circuit in Multisim, attach the Maximum Power load resistor that you found in step 1, then measure the current through the load resistor and voltage across it. Calculate the power dissipated by the load resistor and confirm that it is equal to the value you found in step 2. [Show screenshots] 4) Change the resistor value so that it is 98% of its original value (slightly lower resistance). Then, measure the current through the load resistor and the voltage across it. Calculate the power dissipated by the load resistor, and confirm that it is less than the value you found in steps 2 and 3. 5) Change the resistor value so that it is 102% of its original value (slightly higher resistance). Then, measure the current through the load resistor and the voltage across it. Calculate the power dissipated by the load resistor, and confirm that it is less than the value you found in steps 2 and 3.
Transcribed Image Text:C. 2.2kQ 4702 1kQ 3302 RL = 4.55k2 6802 =6 V 15 V В 1) Determine the value of the load resistor that will dissipate the most power, when connected to the Circuit. (Hint: Use the Thevenin Equivalent circuit). 2) Calculate the current flowing through the load resistor, the voltage across the load resistor, and how much power it dissipates. 3) Using the Circuit in Multisim, attach the Maximum Power load resistor that you found in step 1, then measure the current through the load resistor and voltage across it. Calculate the power dissipated by the load resistor and confirm that it is equal to the value you found in step 2. [Show screenshots] 4) Change the resistor value so that it is 98% of its original value (slightly lower resistance). Then, measure the current through the load resistor and the voltage across it. Calculate the power dissipated by the load resistor, and confirm that it is less than the value you found in steps 2 and 3. 5) Change the resistor value so that it is 102% of its original value (slightly higher resistance). Then, measure the current through the load resistor and the voltage across it. Calculate the power dissipated by the load resistor, and confirm that it is less than the value you found in steps 2 and 3.
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