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- Propert es Rev x E Pypor Fulkers x E Pypor Fulkers x O Mal -Fukersx Thomas, Gebri x nent/d/1gQ-IsBbucwMOGIVPUnbTx13fvoW_HIOYBH70iemw3bw/edit view #2 ☆回 Is Add-ons Help Accessibility Last edit was 2 minutes ago Courior New - - 12 + BIUA 田回- =- 三 : =-E E Properties Review #2 T-=Instructions: Select the best answer, by highlighting your chosen answer, to complete the following questions. 1. Mass divided by volume is the formula for which physical property? a. Weight b. Density which tYpe of properties include color, shape, size, and e Conductivity d. None of the above state of matter? a Physical property 6. Chemical property 3. which of the following is a chemical property of a substance? a. Densily b. Color 4. Which physical property is a size dependent property? a. Mass b. Weight 5. which physical property is a size independent property? a. Color b. Mass C. Mass d. Reacts with acid C. Volume d. AIl of the above c. Boiling point d. Both b and cInbc X (531 X Con X I Bala X Ans X Inbc X CHE X 101 Che X С Ч-С х b My x Unk X Sea X E I ma X app.101edu.co/# Bryant's Gmail Cascadia Canvas Lo... T GSBA Scholarship L... HOMEGROWN TRA... Learn Touch Typing... C The Science of Well... Investor360° ® Login ClickUp Reading list >> Question 7 of 40 Submit Which of the following compounds can form intermolecular hydrogen bonds? A) CH4 B) H2Se C) NH3 D) H2 E) All of these compounds can form hydrogen bonds. 10:36 AM e Type here to search 64°F 小 8/26/2021 (8)Part C F10 BO O 3.04 × 10³ 6.27 x 10-1 The dosage of quinine when a 145-lb adult takes a 200.-mg tablet is equivalent to ug drug per kg of body weight. ► View Available Hint(s) O 627 O 1.38 × 10³ P Pearson * Education Inc. All rights reserved. | Terms of Use Privacy Policy. Permissions Contact Us | Bb Home L End Insert ■ Review |- Constants | Periodic Table 1 2
- Chart 1 ▾ ⠀ H G fr Axis Title F E D 1/T -1.20397 0.003356 -0.59784 0.003145 -0.16252 0.003003 0.262364 0.002874 LN K Chart Title 0.4 0.2 0 0.0034 0.0033 0.0032 0.0031 003 0.0029 0.00282 -0.4 -0.6 -0.8 -1 -1.2 -1.4 TK Axis Title C y=-3033.1x+8.9597 R² = 0.999 298 318 333 348 K -Series1 Linear (Series1) C O B 0.3 0.55 0.85 1.3 + 2 T A > FNM 45 1 25 2 3 60 4 75 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Consider the following data to determine the molar entropy AS°: Temp (°C) Keq 0.3 0.55 0.85 1.3 25 45 60 75 a. 364.82 J/K.mol b. 74.49 J/K.mol c. 86.37 J/K.mol d. 89.59 J/K.mol e. 64.25 J/K.mol Clear my choice351145 TECHNO Define fundamental unit with an example. Why is the unit of force called a derived unit? ic a derived unit? Give its two examples. measurement Dats : D Graphite and iodine a y shine. Explain it with suitable yeasons. Graphite and are non-metals but the iodine are non- metals but REDMI NOTE 10 PRO KBYLWHARNA THAPA A chemical propertie39/99/2021 17:36125Te?
- + e Home ourse.html?courseld=15539865&HepID=676f177415469ec3dc78ff3c8 bf724d9#1 0001 Inbox-Outlook We... S Sugarpill Cosmetic... Shop | Origami Owl Wholesale Glass M... S The Corinthian Hou... zed Invitat... HW Provide Feedback P Pearson Contact Us Copyright 2019 Pearson Education Inc. All rights reserved. Terms of Use Privacy Policy | Permissions MacBook Air »)) DD DII O00 F12 F11 F10 F9 F8 F7 F4 F6 F5 F3 + $ & 3 0 9 4 7 8 6 5 } { P E U R Y D L K G F H T 2LOX Achieve > Students: Register X Assessment - Chem 101 002X nillanlearning.com/courses/55ace5f9-441e-4942-b91a-6dde768c655e/3/k6bu5e/tools/assessment/items/9f6b56a8-92b9-4b ent Check A LGive Up? O Hint OResources Score: 25 Perform the conversions. atm 1.196 atm = 860.8 mmHg = %3D Pa 1386.9 mmHg : atm %3D 287.3 kPa = %3D2 Automobile air bags inflate following a serious impact. The impact triggers the following chemical reaction. 2NaN3 (8)→ 2 Na(s) + 3N₂ (9) S W stry.com/myct/itemView?assignmentProblemID=213377858&attemptNo=2&offset=next X 7 # 3 E D 80 C $ 4 R 888 F V % 5 FS T Y G A Part A 6 B If an automobile air bag has a volume of 11.2 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact? Assume STP conditions. IVE ΑΣΦ Provide Feedback m = Submit MacBook Air F6 Y H & 7 Request Answer N 40 U J * 8 @ C PwC FB I M ( 9 K DD ? O ) O g L command 3 F10 P . : ; Review I Constants I Periodic Table I { + [ option = 11 ? 1 I 323) Next > 1 delete
- 2. The following eight structures are all isomers of C6H14O. Each structure corresponds to one of the predicted ¹H NMR spectra pictured on the next two pages of this document. The integral values for each peak are next to that peak. Indicate which structure matches each spectrum by drawing the structures in the boxes along the right side of the pages. Use the letter codes provided to label the chemically equivalent hydrogens on the structures. One example is provided. Xor A 2H 1H <- A 4H -3₂₂ OH B 2H tot 2 PPM PPM -N 2 PPM N- -~ B 12H DE C 2H 2H 1H B 4H 6H ха по мон F 6H B B B wHow did you get this? k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs 0.693 a 102.0 nanogram(ng) sample of sodium-24 was stored in a lead-lined cabinet for 2.5 days How much sodium-24 remained? The half-life os sodium -24 is 15 hours _________ ng sodium -24 remain check_circle Expert Answer thumb_up thumb_down Step 1 Radioactive decay is a first order reaction. Conversion of days into hours: 1 day2.5 days===24 hrs2.5×2460 hrs1 day=24 hrs2.5 days=2.5×24=60 hrs Calculation of k: k===0.693t1/20.69315 hrs0.0462 hrs−1k=0.693t1/2=0.69315 hrs=0.0462 hrs-1 Step 2 Radioactive decay is a first order reaction, therefore: [A]=[Ao] e−kt[A]=[Ao] e-kt where [A] is the final amount remained at time t, [Ao] is the initial amount. Putting values: [A]====102.0 ng×e−0.0462 hrs−1×60 hrs102.0 ng×e−2.772102.0 ng×0.062546.38 ng[A]=102.0 ng×e-0.0462 hrs-1×60 hrs=102.0 ng×e-2.772=102.0 ng×0.06254=6.38 ng Thus 6.38 ng of sodium-24 remained.15. You are calibrating a buret that is graduated to 0.1 mL. The measured volume delivered is 10.88 mL at 24.000°C. The calculated actual volume based on the mass of water is 10.859 mL. IMPORTANT: The actual volume is reported to 2 decimal places since the buret volume is reported to 1/100 of a mL. The buret error (mL) is: -0.02 0.02 -0.021 0.021