2. When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The balanced chemical equation is: Pb(NO3)2 (aq) + 2 Nal (aq) → Pbl2 (s) + 2 NaNO3 (aq) a. If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed? b. What is the limiting reagent? c. How many grams of lead (II) iodide is formed? d. If 6 grams of sodium nitrate are actually formed in the reaction described in problem #2, what is the percent yield of this reaction?

2. When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The balanced chemical equation is: Pb(NO3)2 (aq) + 2 Nal (aq) → Pbl2 (s) + 2 NaNO3 (aq) a. If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed? b. What is the limiting reagent? c. How many grams of lead (II) iodide is formed? d. If 6 grams of sodium nitrate are actually formed in the reaction described in problem #2, what is the percent yield of this reaction?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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