Cr2(SO4)3 reacts with BaCl2 in aqueous solutions to produce a precipitate of BaSO4 that can be filtered and weighed. The balanced equation for the reaction is: Cr2(SO4)3 (aq) + 3 BaCl2 (aq) → 3 BaSO4 (s) + 2CrCl3 (aq) Suppose you have a mixture that contains Cr2(SO4)3, plus other compounds that do not react with BaCl2. If 0.3686 g of the mixture yields 0.4103 g of BaSO4, what is the percentage of Cr2(SO4)3 in the mixture? Molar masses: Cr2(SO4)3 392.18 g/mol BaSO4 233.39 g/mol
Cr2(SO4)3 reacts with BaCl2 in aqueous solutions to produce a precipitate of BaSO4 that can be filtered and weighed. The balanced equation for the reaction is: Cr2(SO4)3 (aq) + 3 BaCl2 (aq) → 3 BaSO4 (s) + 2CrCl3 (aq) Suppose you have a mixture that contains Cr2(SO4)3, plus other compounds that do not react with BaCl2. If 0.3686 g of the mixture yields 0.4103 g of BaSO4, what is the percentage of Cr2(SO4)3 in the mixture? Molar masses: Cr2(SO4)3 392.18 g/mol BaSO4 233.39 g/mol
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Cr2(SO4)3 reacts with BaCl2 in aqueous solutions to produce a precipitate of BaSO4 that can be filtered
and weighed. The balanced equation for the reaction is:
Cr2(SO4)3 (aq) + 3 BaCl2 (aq) → 3 BaSO4 (s) + 2CrCl3 (aq)
Suppose you have a mixture that contains Cr2(SO4)3, plus other compounds that do not react with BaCl2. If
0.3686 g of the mixture yields 0.4103 g of BaSO4, what is the percentage of Cr2(SO4)3 in the mixture?
Molar masses: Cr2(SO4)3 392.18 g/mol BaSO4 233.39 g/mol
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