KOH(aq) + HNO3(aq) → H₂O(1) + KNO3(aq)

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Could I have some help with determining the ionic equation of these two formulas?

The chemical equation depicted illustrates a neutralization reaction:

KOH(aq) + HNO₃(aq) → H₂O(l) + KNO₃(aq)

- **KOH(aq)**: Potassium hydroxide in aqueous solution, a strong base.
- **HNO₃(aq)**: Nitric acid in aqueous solution, a strong acid.
- **H₂O(l)**: Water, a common product of acid-base reactions.
- **KNO₃(aq)**: Potassium nitrate in aqueous solution, a salt formed from the reaction.

In this reaction, potassium hydroxide reacts with nitric acid to produce water and potassium nitrate. This is a classic example of an acid reacting with a base to form a salt and water, demonstrating an essential concept in chemistry known as neutralization.
Transcribed Image Text:The chemical equation depicted illustrates a neutralization reaction: KOH(aq) + HNO₃(aq) → H₂O(l) + KNO₃(aq) - **KOH(aq)**: Potassium hydroxide in aqueous solution, a strong base. - **HNO₃(aq)**: Nitric acid in aqueous solution, a strong acid. - **H₂O(l)**: Water, a common product of acid-base reactions. - **KNO₃(aq)**: Potassium nitrate in aqueous solution, a salt formed from the reaction. In this reaction, potassium hydroxide reacts with nitric acid to produce water and potassium nitrate. This is a classic example of an acid reacting with a base to form a salt and water, demonstrating an essential concept in chemistry known as neutralization.
**Chemical Reaction:**

In this double replacement reaction, sodium phosphate and iron(III) chloride react in aqueous solutions to form iron(III) phosphate as a solid precipitate and sodium chloride in aqueous form.

**Chemical Equation:**

\[ \text{Na}_3\text{PO}_4\,(aq) + \text{FeCl}_3\,(aq) \rightarrow \text{FePO}_4\,(s) + \text{NaCl}\,(aq) \]

**Explanation:**

- **Reactants:**
  - Sodium Phosphate \((\text{Na}_3\text{PO}_4)\) is in aqueous form.
  - Iron(III) Chloride \((\text{FeCl}_3)\) is also in aqueous form.

- **Products:**
  - Iron(III) Phosphate \((\text{FePO}_4)\) forms as a solid, indicating it precipitates out of the solution.
  - Sodium Chloride \((\text{NaCl})\) remains in aqueous solution.

This reaction demonstrates the principles of solubility and precipitation in chemistry.
Transcribed Image Text:**Chemical Reaction:** In this double replacement reaction, sodium phosphate and iron(III) chloride react in aqueous solutions to form iron(III) phosphate as a solid precipitate and sodium chloride in aqueous form. **Chemical Equation:** \[ \text{Na}_3\text{PO}_4\,(aq) + \text{FeCl}_3\,(aq) \rightarrow \text{FePO}_4\,(s) + \text{NaCl}\,(aq) \] **Explanation:** - **Reactants:** - Sodium Phosphate \((\text{Na}_3\text{PO}_4)\) is in aqueous form. - Iron(III) Chloride \((\text{FeCl}_3)\) is also in aqueous form. - **Products:** - Iron(III) Phosphate \((\text{FePO}_4)\) forms as a solid, indicating it precipitates out of the solution. - Sodium Chloride \((\text{NaCl})\) remains in aqueous solution. This reaction demonstrates the principles of solubility and precipitation in chemistry.
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