A chemistry student carries out this reaction, beginning with 2.10 grams of NaBr and 3.25 grams of Pb(NO3)2: (First, balance the reaction if needed) NaBr (aq) + Pb (NO3)2 (aq) →PbBr2 (s) + NaNO3 (aq) Which starting material is the limiting reagent? What is the theoretical yield of PbBr2, in this reaction? If the student actually isolates 3.5 g of PbBr2, what is the percent yield of the reaction?
A chemistry student carries out this reaction, beginning with 2.10 grams of NaBr and 3.25 grams of Pb(NO3)2: (First, balance the reaction if needed) NaBr (aq) + Pb (NO3)2 (aq) →PbBr2 (s) + NaNO3 (aq) Which starting material is the limiting reagent? What is the theoretical yield of PbBr2, in this reaction? If the student actually isolates 3.5 g of PbBr2, what is the percent yield of the reaction?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A chemistry student carries out this reaction, beginning with 2.10 grams of NaBr and 3.25 grams of Pb(NO3)2: (First, balance the reaction if needed)
NaBr (aq) + Pb (NO3)2 (aq) →PbBr2 (s) + NaNO3 (aq)
- Which starting material is the limiting reagent?
- What is the theoretical yield of PbBr2, in this reaction?
- If the student actually isolates 3.5 g of PbBr2, what is the percent yield of the reaction?
Expert Solution

Step 1
Initially,
mass of NaBr = 2.10g
Mass of Pb(NO3)2 = 3.25g
The balanced chemical equation is
2NaBr (aq) + Pb(NO3)2 (aq) PbBr2 (s)+ 2NaNO3 (aq)
from the above balanced equation it is clear that,
2 mole of NaBr require 1 mole of Pb(NO3)2
now finding their no of moles:
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