2. When 1.3 g of C4H9NO is dissolved in 150 mL water, the resulting solution is 0.50% ionized at equilibrium. a. Calculate the pKb for C4H9NO. Answer: b. 5.5 mL of 1.5 M HCl is added to the solution. Calculate the equilibrium [C4H9NO], [C4H9NOH*], [H3O+], [OH-], and [CI-] in the solution. [C4H9NO]: [C4H9NOH+]: [H3O+]: [OH-]: [CI-]:

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2. When 1.3 g of C4H9NO is dissolved in 150 mL water, the resulting solution is 0.50% ionized at
equilibrium.
a. Calculate the pKb for C4H9NO.
Answer:
b. 5.5 mL of 1.5 M HCl is added to the solution. Calculate the equilibrium [C4H9NO], [C4H9NOH+],
[H3O+], [OH-], and [Cl-] in the solution.
[C4H9NO]:
[C4H9NOH+]:
[H3O+]:
[OH-]:
[CI-]:
Transcribed Image Text:2. When 1.3 g of C4H9NO is dissolved in 150 mL water, the resulting solution is 0.50% ionized at equilibrium. a. Calculate the pKb for C4H9NO. Answer: b. 5.5 mL of 1.5 M HCl is added to the solution. Calculate the equilibrium [C4H9NO], [C4H9NOH+], [H3O+], [OH-], and [Cl-] in the solution. [C4H9NO]: [C4H9NOH+]: [H3O+]: [OH-]: [CI-]:
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