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2. What is the slope of the normal line to the curve 4x2 - 9y2 = 1 at point (3,2) ? a. 3 b. - 8. С. d. - 3. What is the equation of the tangent line to the curve 4x² – 9y2 = 1 at point (3,2) ? a. y =x - 4 b. y = x 4. What is the equation of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? y =x- 4 c. y =x+ 4 -3x+13 d. y = c. y = * -3x+13 b. y = x + 4 d. y = X - 4

2. What is the slope of the normal line to the curve 4x2 - 9y2 = 1 at point (3,2) ? a. 3 b. - 8. С. d. - 3. What is the equation of the tangent line to the curve 4x² – 9y2 = 1 at point (3,2) ? a. y =x - 4 b. y = x 4. What is the equation of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? y =x- 4 c. y =x+ 4 -3x+13 d. y = c. y = * -3x+13 b. y = x + 4 d. y = X - 4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Answer question number 2 and 4.
2. What is the slope of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? b. - 8 С. d. - a. 2 3. What is the equation of the tangent line to the curve 4x2 – 9y² = 1 at point (3,2) ? a. y =x- 4 b. y = x 4. What is the equation of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? y =x-4 C. y =x + 4 -3x+13 d. y = %3D -3x+13 b. y =x+4 C. y = x d. y =
Transcribed Image Text:2. What is the slope of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? b. - 8 С. d. - a. 2 3. What is the equation of the tangent line to the curve 4x2 – 9y² = 1 at point (3,2) ? a. y =x- 4 b. y = x 4. What is the equation of the normal line to the curve 4x2 – 9y2 = 1 at point (3,2) ? y =x-4 C. y =x + 4 -3x+13 d. y = %3D -3x+13 b. y =x+4 C. y = x d. y =
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