В. 5. We let y(t) be the position function. What is the position function? A. p(t) = - 16t2 - 100 t +C B. p(t) = - 16t2 - 100 t 6. What is the value of C in the position function? A. - 100 B. - 100, 000 7. What is the final position function (with the value of C substituted)? A. (t) = - 16t² – 100 t-100 B. p(t) = - 16t2 – 100 t - 100,000 C. p(t) = - 16t2 + 100 t +C D. p(t) = - 16t2 + 100 t - C C. 100 D. 100, 000 C. p(t) = - 16t2 + 100 t + 100 D. p(t) = - 16t² + 100 t + 100,000 %3D e per ho ur (66 feet per s econd
В. 5. We let y(t) be the position function. What is the position function? A. p(t) = - 16t2 - 100 t +C B. p(t) = - 16t2 - 100 t 6. What is the value of C in the position function? A. - 100 B. - 100, 000 7. What is the final position function (with the value of C substituted)? A. (t) = - 16t² – 100 t-100 B. p(t) = - 16t2 – 100 t - 100,000 C. p(t) = - 16t2 + 100 t +C D. p(t) = - 16t2 + 100 t - C C. 100 D. 100, 000 C. p(t) = - 16t2 + 100 t + 100 D. p(t) = - 16t² + 100 t + 100,000 %3D e per ho ur (66 feet per s econd
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Answer question number 5-7.
![Use the word problem below to answer questions 1-7.
An object's downward acceleration is given by y"(t) = -32 ft/sec2. Assume that the initial
velocity is y'(0) = -100ft/s and the initial position is y(0) = 100, 000 ft.
1. Evaluate fy"(t) dt.
A. -32 +C
В. -32€
2. We let V(t) the velocity function. What is V(t)?
A. V(t) = -32 +C
B. V(t) = -32
3. What is the value of C in the velocity function?
A. - 100
B. -32
4. What is Sy'(t)dt?
A. - 16t2 – 100 t + C
B. - 16t2 - 100 t
5. We let y(t) be the position function. What is the position function?
A. p(t) = - 16t² – 100 t + C
B. p(t) = - 16t² – 100 t
6. What is the value of C in the position function?
A. - 100
B. - 100, 000
7. What is the final position function (with the value of C substituted)?
A. (t) = - 16t2 – 100 t - 100
B. p(t) = - 16t2 – 100 t – 100,000
8- 10. A car is travelling along a straight, level road at 45 miles per hour (66 feet per second)
when the driver is forced to apply the brakes to avoid an accident. The brakes supply
a constant deceleration of 22ft/sec? (feet per second, per second), how far does the
car travel before coming to a complete stop?
A. 99ft
B. 297 ft
C. -32t + C
D. -32
C. V(t) = -32t + C
D. V(t) = -32t
C. 100
D. 32
C. - 16t2 + 100 t +C
D. - 16t2 + 100 t-C
В.
C. p(t) = - 16t² + 100 t + C
D. p(t) = - 16t² + 100 t – C
%3D
C. 100
D. 100, 000
C. p(t) = - 16t² + 100 t + 100
D. p(t) = - 16t² + 100 t + 100,000
C. 99 mi.
D. 36 ft](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6552a003-474f-4d3a-9b04-d12605186ec7%2F25454b84-1ec9-4908-9f9f-38804f651954%2Fmw56f4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the word problem below to answer questions 1-7.
An object's downward acceleration is given by y"(t) = -32 ft/sec2. Assume that the initial
velocity is y'(0) = -100ft/s and the initial position is y(0) = 100, 000 ft.
1. Evaluate fy"(t) dt.
A. -32 +C
В. -32€
2. We let V(t) the velocity function. What is V(t)?
A. V(t) = -32 +C
B. V(t) = -32
3. What is the value of C in the velocity function?
A. - 100
B. -32
4. What is Sy'(t)dt?
A. - 16t2 – 100 t + C
B. - 16t2 - 100 t
5. We let y(t) be the position function. What is the position function?
A. p(t) = - 16t² – 100 t + C
B. p(t) = - 16t² – 100 t
6. What is the value of C in the position function?
A. - 100
B. - 100, 000
7. What is the final position function (with the value of C substituted)?
A. (t) = - 16t2 – 100 t - 100
B. p(t) = - 16t2 – 100 t – 100,000
8- 10. A car is travelling along a straight, level road at 45 miles per hour (66 feet per second)
when the driver is forced to apply the brakes to avoid an accident. The brakes supply
a constant deceleration of 22ft/sec? (feet per second, per second), how far does the
car travel before coming to a complete stop?
A. 99ft
B. 297 ft
C. -32t + C
D. -32
C. V(t) = -32t + C
D. V(t) = -32t
C. 100
D. 32
C. - 16t2 + 100 t +C
D. - 16t2 + 100 t-C
В.
C. p(t) = - 16t² + 100 t + C
D. p(t) = - 16t² + 100 t – C
%3D
C. 100
D. 100, 000
C. p(t) = - 16t² + 100 t + 100
D. p(t) = - 16t² + 100 t + 100,000
C. 99 mi.
D. 36 ft
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