2. Tin (Sn) obeys Henry's law in dilute liquid solutions of Sn (solute) in Cd (solvent) and the Henrian activity coefficient of Sn, ºSn. varies with temperature as Ln ysa= -840/T+1.58 Calculate the change in temperature when 2 mole of liquid Sn and 98 moles of liquid Cd are mixed in an adiabatic enclosure. The molar constant pressure heat capacity of the liquid alloy formed is 29.5 J/K.
2. Tin (Sn) obeys Henry's law in dilute liquid solutions of Sn (solute) in Cd (solvent) and the Henrian activity coefficient of Sn, ºSn. varies with temperature as Ln ysa= -840/T+1.58 Calculate the change in temperature when 2 mole of liquid Sn and 98 moles of liquid Cd are mixed in an adiabatic enclosure. The molar constant pressure heat capacity of the liquid alloy formed is 29.5 J/K.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:2. Tin (Sn) obeys Henry's law in dilute liquid solutions of Sn (solute) in Cd (solvent) and
the Henrian activity coefficient of Sn, y°sn. varies with temperature as
Ln y°su= -840/T+1.58
Calculate the change in temperature when 2 mole of liquid Sn and 98 moles of liquid Cd
are mixed in an adiabatic enclosure. The molar constant pressure heat capacity of the
liquid alloy formed is 29.5 J/K.
a) Using the plot of XcuXFe Vs. log yCu below,
a) Calculate the activity coefficient and activity of the Fe at X Cu =0.75 (write the
equation for that). Use graphical approximate solution and explain briefly how you get
it.
b) Calculate the partial pressure of Fe over Cu-Fe liquid solution at Xcu-0.5 at
1550°C.
Ln pFe ° (L) (atm) =-45390/T-1.27LNT +23.93
c) Does Cu-Fe liquid solution obey regular solution model? Show with at least three data.
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