2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yov= 1,005' PVI Highest eleyation

2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00 with its elevation of 1,005 ft. Please determine following. a. PVC station b. PVC elevation C. PVT station d. PVT elevation e. The station where the highest elevation is located f. The highest elevation on the road g. The stations where the road elevation is 995 feet. Crest Vertical Curve PVI = 110+00 sta Design Speed: 70 mph Yov= 1,005' PVI Highest eleyation

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

2. There is an equal-tangent vertical curve, which is 1,115 ft long. It connects an initial
grade of +2.5% and a final grade of -1.0%. PVI of the vertical curve is at station 110 + 00
with its elevation of 1,005 ft. Please determine following.
a. PVC station
b. PVC elevation
C. PVT station
d. PVT elevation
e. The station where the highest elevation is located
f. The highest elevation on the road
g. The stations where the road elevation is 995 feet.
Crest Vertical Curve
PVI = 110+00
sta
Design Speed: 70 mph
Yev= 1,005'
PVI
Highest elevation
PVI
2.5%
-2.0%
PVC
PVT
Elevation
= 995 ft
L=1,115 ft

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