2. Industrially, vanadium metal, which is used in steel alloys, can be obtained by reacting vanadium(V) oxide with calcium at high temperatures: Ca + V,0, --> Cao + V In one process, 1.54x 10° g of V,O, (MM = 181.88g/mol) react with 1.96 x10° g of Ca. (MM = 40.08g/mol) %3D (A) Determine the limiting reactant. (B) Determine the excess reactant. (C) Calculate the theoretical yield of V. (MM = 50.94g/mol) (D) Calculate the percent yield if 803 g of V are actually obtained.
2. Industrially, vanadium metal, which is used in steel alloys, can be obtained by reacting vanadium(V) oxide with calcium at high temperatures: Ca + V,0, --> Cao + V In one process, 1.54x 10° g of V,O, (MM = 181.88g/mol) react with 1.96 x10° g of Ca. (MM = 40.08g/mol) %3D (A) Determine the limiting reactant. (B) Determine the excess reactant. (C) Calculate the theoretical yield of V. (MM = 50.94g/mol) (D) Calculate the percent yield if 803 g of V are actually obtained.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:1. Mr. Ivan , has discovered the following new elements with their respective molar masses and charge:
Element
Chemical Symbol
Molar Mass (in g/mol)
Oxidation Number (Charge)
Pestingyawa
Pe
10 g/mol
+2
Tiburcium
T
100 g/mol
+4
Mamshie
Ma
50 g/mol
-2
Ludine
Lu
20 g/mol
-4
100 g of Pestingyawa Mamshide (PeMa) reacted with 60 g Tiburcium Ludide (TLu) via double displacement
reaction, forming Pestingyawa Ludide and Tiburcium Mamshide. If the Percent Yield of Tiburcium Mamshide is
only 50%, what is its actual yield (in grams)?
2. Industrially, vanadium metal, which is used in steel alloys, can be obtained by reacting vanadium(V)
oxide with calcium at high temperatures:
Ca + V,0, --> Cao + V
In one process, 1.54x 10° g of V,O, (MM = 181.88g/mol) react with 1.96 x10° g of Ca. (MM = 40.08g/mol)
(A) Determine the limiting reactant.
(B) Determine the excess reactant.
(C) Calculate the theoretical yield of V. (MM = 50.94g/mol)
(D) Calculate the percent yield if 803 g of V are actually obtained.
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