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Trial -1>. what is volune of. Trial-1 Volume of NAOH in Liters. Moles of NaOH (M×V) Moles of CH,COOH Molar Mass Of CH;COOH (g/mol) How Mass of CH,COOH (grams) Volume of Vinegar(mL) Weight/volume percent of acetic acid in vinegar (%) 1b. The true value(accepted value) % (w/v) of the vinegar was found to be 3.25 %. Calculate the percent error by using the value(measured value) that you calculated.

Trial -1>. what is volune of. Trial-1 Volume of NAOH in Liters. Moles of NaOH (M×V) Moles of CH,COOH Molar Mass Of CH;COOH (g/mol) How Mass of CH,COOH (grams) Volume of Vinegar(mL) Weight/volume percent of acetic acid in vinegar (%) 1b. The true value(accepted value) % (w/v) of the vinegar was found to be 3.25 %. Calculate the percent error by using the value(measured value) that you calculated.

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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2 Trial -1->. what is volue of. Trial-1 Volume of NaOH in Liters. Moles of NaOH (MxV) Moles of CH,COOH Molar Mass Of CH,COOH (g/mol) Mass of CH,COOH (grams) Volume of Vinegar(mL) Weight/volume percent of acetic acid in vinegar (%) 1b. The true value(accepted value) % (w/v) of the vinegar was found to be 3.25 %. Calculate the percent error by using the value(measured value) that you calculated.
Transcribed Image Text:2 Trial -1->. what is volue of. Trial-1 Volume of NaOH in Liters. Moles of NaOH (MxV) Moles of CH,COOH Molar Mass Of CH,COOH (g/mol) Mass of CH,COOH (grams) Volume of Vinegar(mL) Weight/volume percent of acetic acid in vinegar (%) 1b. The true value(accepted value) % (w/v) of the vinegar was found to be 3.25 %. Calculate the percent error by using the value(measured value) that you calculated.
nplete calculations and report answers in appropriate significant figures and units. la. In an experiment to determine the amount of acetic acid present in the given volume of vinegar, following data was obtained.The chemical reaction between acetic acid(in vinegar) and sodium hydroxide(base) is given below: CH;COOH(aq)+ NaOH(aq) → CH,COONA(aq)+ H,O(!) At equivalence point: moles of NaOH = moles of CH;COOH Molarity of NAOH solution = MNaOH = 0.100 M Complete calculations using the following data: Trial-1 Volume of Vinegar in Flask 2.00 mL Initial reading of NaOH in the buret in mL 2.05 Final reading of NaOH in the buret in mL 12.34 Total volume of NaOH used (Show calculations) in mL. Trial-1 V Initial Total Volume of NaOH solution used (in mL) =VFinal - = V NaOH Total Volume of NaOH solution used(in Liters) Moles of NaOH =(MNaOH VNaOH) Moles of Acetic acid = Mass of acetic acid in vinegar in grams (Use molar mass of acetic acid) : Volume of Vinegar used: 2.00 mL Weight/volume percent of acetic acid in vinegar %(w/v) =
Transcribed Image Text:nplete calculations and report answers in appropriate significant figures and units. la. In an experiment to determine the amount of acetic acid present in the given volume of vinegar, following data was obtained.The chemical reaction between acetic acid(in vinegar) and sodium hydroxide(base) is given below: CH;COOH(aq)+ NaOH(aq) → CH,COONA(aq)+ H,O(!) At equivalence point: moles of NaOH = moles of CH;COOH Molarity of NAOH solution = MNaOH = 0.100 M Complete calculations using the following data: Trial-1 Volume of Vinegar in Flask 2.00 mL Initial reading of NaOH in the buret in mL 2.05 Final reading of NaOH in the buret in mL 12.34 Total volume of NaOH used (Show calculations) in mL. Trial-1 V Initial Total Volume of NaOH solution used (in mL) =VFinal - = V NaOH Total Volume of NaOH solution used(in Liters) Moles of NaOH =(MNaOH VNaOH) Moles of Acetic acid = Mass of acetic acid in vinegar in grams (Use molar mass of acetic acid) : Volume of Vinegar used: 2.00 mL Weight/volume percent of acetic acid in vinegar %(w/v) =
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