MAN If you want to consume 75 mg of vitamin C, how many mL of cranberry juice n you drink? Cranberry juice is 0.01% (w/v) vitamin C. Show your process for solving problem, including clearly showing units. you want 12 Pelar ding
MAN If you want to consume 75 mg of vitamin C, how many mL of cranberry juice n you drink? Cranberry juice is 0.01% (w/v) vitamin C. Show your process for solving problem, including clearly showing units. you want 12 Pelar ding
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Here's the transcription of the text and a brief instructional on how to solve the problem, ideal for an educational website:
---
### Problem Statement:
If you want to consume 75 mg of vitamin C, how many mL of cranberry juice must you drink? Cranberry juice is 0.01% (w/v) vitamin C. Show your process for solving this problem, including clearly showing units.
---
### Solution Process:
1. **Understand the given information:**
- **Desired intake of vitamin C:** 75 mg
- **Concentration of vitamin C in cranberry juice:** 0.01% (w/v)
- This means 0.01 grams of vitamin C per 100 mL of cranberry juice.
2. **Convert the percentage concentration to a usable form:**
- Since 0.01% (w/v) is equivalent to 0.01 grams per 100 mL, we know:
\[
\text{Concentration} = \frac{0.01 \text{ grams}}{100 \text{ mL}} = 0.0001 \text{ grams/mL}
\]
3. **Convert the desired intake of vitamin C from mg to grams:**
- Given intake: 75 mg
- Conversion factor: 1 gram = 1000 mg
\[
75 \text{ mg} = \frac{75}{1000} \text{ grams} = 0.075 \text{ grams}
\]
4. **Set up the equation to find out how many mL of cranberry juice you need:**
- Let \( x \) be the volume of cranberry juice in mL.
- Since concentration \( \times \) volume gives the amount of vitamin C, we get:
\[
0.0001 \text{ grams/mL} \times x \text{ mL} = 0.075 \text{ grams}
\]
- Solve for \( x \):
\[
x = \frac{0.075 \text{ grams}}{0.0001 \text{ grams/mL}} = 750 \text{ mL}
\]
Thus, to consume 75 mg of vitamin C, you need to drink 750 mL of cranberry juice.
---
This problem demonstrates how to apply concentration and unit conversion calculations in practical scenarios.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Febe45f5d-5c04-4921-8d3a-3c73b83ec869%2F42b38365-abc7-4f8b-9653-789319ae4cf0%2F0ct9nt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Here's the transcription of the text and a brief instructional on how to solve the problem, ideal for an educational website:
---
### Problem Statement:
If you want to consume 75 mg of vitamin C, how many mL of cranberry juice must you drink? Cranberry juice is 0.01% (w/v) vitamin C. Show your process for solving this problem, including clearly showing units.
---
### Solution Process:
1. **Understand the given information:**
- **Desired intake of vitamin C:** 75 mg
- **Concentration of vitamin C in cranberry juice:** 0.01% (w/v)
- This means 0.01 grams of vitamin C per 100 mL of cranberry juice.
2. **Convert the percentage concentration to a usable form:**
- Since 0.01% (w/v) is equivalent to 0.01 grams per 100 mL, we know:
\[
\text{Concentration} = \frac{0.01 \text{ grams}}{100 \text{ mL}} = 0.0001 \text{ grams/mL}
\]
3. **Convert the desired intake of vitamin C from mg to grams:**
- Given intake: 75 mg
- Conversion factor: 1 gram = 1000 mg
\[
75 \text{ mg} = \frac{75}{1000} \text{ grams} = 0.075 \text{ grams}
\]
4. **Set up the equation to find out how many mL of cranberry juice you need:**
- Let \( x \) be the volume of cranberry juice in mL.
- Since concentration \( \times \) volume gives the amount of vitamin C, we get:
\[
0.0001 \text{ grams/mL} \times x \text{ mL} = 0.075 \text{ grams}
\]
- Solve for \( x \):
\[
x = \frac{0.075 \text{ grams}}{0.0001 \text{ grams/mL}} = 750 \text{ mL}
\]
Thus, to consume 75 mg of vitamin C, you need to drink 750 mL of cranberry juice.
---
This problem demonstrates how to apply concentration and unit conversion calculations in practical scenarios.
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