2. For the following compound gear train determine the angular velocity of gear 6.W2@₂ = 1800 rpmT₂ = 1200Lbf-inN₂(Driver)N₂ = 17 teeth6N₁ = 28 teeth№6Ns(Driven)N=12 teethN₁ = 38 teethN6 = 24 teeth

We need to understand how a compound gear train works to determine the angular velocity of gear 6…

Answered: 2. For the following compound gear…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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1. For the following simple gear train determine the angular velocity and torque of gear 6. 2 A M₂ @₁ = 1800 rpm T₂ = 1200lbf-in N₂ = 17 teeth N₁ = 28 teeth N₁ = 12 teeth N N₁ = 38 teeth N6 = 24 teeth N6 FIGURE 9-28 A simple gear train
3. For the following planetry gear train determine the following -Internal gear connected to drive shaft, 427 Sun gear: -Planet pinions, 127 Planet carrier connected to transmission Figure not to scale. N2 = 24 teeth, Input to Sun gear: w₂ = 100 rpm ccw, T₂ = 1000 lbf-in Input to Ring gear: ws = 240 rpm cw a. Determine the angular velocity of the carrier. (units and direction). b. Determine the torque on the arm.
6. 5 3 Arm 6. 2 Arm Arm 2 3 1 Bearing Given N2 = 30, N3 = 25, N4 =45, N5 = 40, N6 = 200 W2 = 240 rpm ccw, warm = 120 rpm cw, T2 = 12 ft-lb Show your work. Answers without work will not be accepted a. Identify the gear sets. b. Determine the velocity gear train ratio and the angular velocity of gear 6. c. Determine the torque gear train ratio and output torque of gear 6.
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Number of Teeth on Gears A, B, C, D, E and F are 40, 132, 50, 120, 50 and 116 respectively. Gear A rotates Clockwise and is connected to a motor spinning at 900 RPM. What is the RPM and rotational direction (Clockwise/Anticlockwise) of various gears, and the final output RPM and rotation direction on shaft of gear F? What is the overall speed reduction of the drive train?
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2. The following data is for the gear train shown in the figure: Given: N2 = 30t, N3 = 35t, N4 = 55t, N5 = 40t, N6 = 50t, N7 = 40t %3D w2 = 30 rpm ccw, warm = 20 rpm cw, Input torque on gear 2 is 1200 lbf.in Determine the following: a. Angular velocity of the sun gear. b. The gear ratio R required to determine the angular velocity of gear 6. c. The angular velocity of gear 6. d. The angular velocity of gear 7. e. Output torque on gear 7. Be careful with your units. Arm 6 ... 7
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Q2/ Two mating involute spur gears of 20* pressure angle have a gear ratio of 2. The number of teeth on the pinion is 20 and its speed is 250 r.p.m. The module pitch of teeth is 10 mm. If the addendum on cach wheel is such that the path of approach and the path of recess on cach side are half the maximum possible length each, find: i) the addendum for pinion and gear wheel, ii) the length of arc of contact, iii)the maximum velocity of sliding during approach and recess. Assume pinion to be driver.
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Hello good Afternoon Sir, Permission, i have a question in my homework. The following bellow is question. Please advice. Thank you Regards,Irfan In planning the combined gears of the Ferguson planetary paradox as shown in the figure below.Sun gear hand input with angular speed (w2) = 0 rpm and hand input with angular speed (w.arm) = 400 rpm counterclockwise (ccw)Where is the number of teeth:Sun gear N2 = 100 (external gear)Sun gear N3 = 99 (external gear)Sun gear N4 = 101 (external gear)Planet gear N5 = 20 (external gear)Calculate the angular velocity, for each gear using the tabulation method. The data is in the image below
Q3: For the gear trains shown below, What is the velocity and direction of output gear? GEAR D В 60T GEAR A 201 GEAR C DRIVER GEAR ROTATING AT 200 RPM 150T 10T ANT-CLOCKWISE DRIVEN GEAR 251 100 revs/min By VRyan 100T 50T 20 TEETH 10 TEETH 60 REVS/MIN

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2. For the following compound gear train determine the angular velocity of gear 6. W2 @₂ = 1800 rpm T₂ = 1200Lbf-in N₂ (Driver) N₂ = 17 teeth 6 N₁ = 28 teeth №6 Ns (Driven) N=12 teeth N₁ = 38 teeth N6 = 24 teeth