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Find the Optimal solution using UV/MOID method for the following problem
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Demand
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- A water company owns water pipes that burst often due to poor maintenance. The company can invest GHS m in the maintenance of the pipes. More maintenance means less water loss through bursts and fewer compensation payments to residents due to flooding of their properties. Assume that the value of lost water is 1/m so that more maintenance reduces the amount of loss. Assume that the value of damage to properties where the pipes are routed is 3/m , so that more maintenance decreases the amount of damage to properties. (i.) What is the socially optimal level of maintenance, m? What is the associated value of lost water and property damage? (Note: Minimize the total cost function) ( ii). What level of m is chosen when pipes that burst run through land owned by the government (the company pays nothing for damages even though there is still some damage associated with pipe bursts)? What is the new value for property damage? What is the deadweight loss?Find B - A. 4 9 - 5 7 A = B = 2 8 3 - 5 B-A =The problems with e.g."Acid rain" created by emissions of sulfur dioxide has been onemajor problem in Sweden, not least because emissions have occurred in other countries (eg England and Denmark) andthen transported here. Now assume that if one tonne of sulfur is emitted in England, it results in one (1) gram of sulfur deposition in Sweden. The corresponding deposit of one tonne of sulfur emissions in Denmark is assumed to be 3 grams. Suppose further that The socio-economic damage of one gram of sulfur deposit can be estimated at SEK 0.10.The marginal cost of reduce sulfur emissions in England is estimated at Z SEK per tonne, and in Denmark the equivalent is estimatedcost to 2Z SEK per tonne. Z indicates here the emission reduction in tonnes (eg in Denmark it would cost SEK 4 toreduce emissions by two tonnes). In other words, Z = 0 corresponds to the emission level where there is no reductionemissions occur. a) Suppose now that the European Union decides that Denmark and England…
- The frequency of breakdown of a machine per month is shown in the table. The cost ofa breakdown is $1,000 and the cost of preventive maintenance is $1,250 per month. Ifpreventive maintenance is performed, the probability of a machine breakdown is negligible. Should the manager use preventive maintenance, or would it be cheaper to repair themachine when it breaks down?Number of breakdowns 0 1 2 3Frequency of occurrence .20 .30 .40 .10The data from 200 machined parts are summarizedas follows:y yesdepth of boreE, noabovebelowedge conditioncoarsetarget15target10moderatesmooth25205080(a) What is the probability that a part selected has a moderateedge condition and a below-target bore depth?(b) What is the probability that a part selected has a moderateedge condition or a below-target bore depth?(c) What is the probability that a part selected does not have amoderate edge condition or does not have a below-targetbore depth?(d) Construct a Venn diagram representation of the events inthis sample space.For all parts of this question, assume that the log of GDP per capita is normally distributed with a mean of 8.7 and standard devistion of 1.5Step 1 of 4: If the log of the world distribution of income is normaly distributed with a mean of 8.7 and a standard deviation of 1.5, what income indollars) marks the 90th percentile? KeypadAnswer A 71.325B 1.29C 41,253D 10.63
- Y 0 500 1000 1500 2000 2500 3000 3500 4000 C 200 600 1000 1400 1800 2200 2600 3000 34000 S -200 -100 0 100 200 300 400 500 600 a) S= -200Y. b) C = -200 + Y. c) C =-200+ 0.2Y. d) C = -200 + 0.8Y. e) C = 200+ 0.8Y. I 200 200 200 200 200 200 200 200 200 G 500 500 500 500 500 500 500 500 500 X 400 400 400 400 400 400 400 400 400 IM 100 150 200 250 300 350 400 450 500 XN AE 1. Refer to the data above to answer this question. What is the equation for the saving function? 2. Refer to the data above to answer this question. What is the equation for the net export function? a) AN = 300. b) XN = 400 - 300Y. c) XN = 300 - 50Y. d) XN = 300 + 0.1Y. e) AN= 300 -0.1Y.5#14 Control Charts: Yellowstone National Park Yellowstone Park Medical Services provides emergency health care for park visitors. The average number of visitors treated is 21.7 per day during the summer period. The estimated standard deviation is 4.2 visitors. a. For a 10-day summer period, the following data show the number of visitors treated each day. Day 1 2 3 4 5 6 7 8 9 10 # 25 19 17 15 20 24 30 19 16 23 Make a control chart for the daily number of visitors treated and plot the data on the control chart. Does the data indicate that the number visitors treated is "in Control"? b. For another 10-day summer period, the following data saw obtained. Day 1 2 3 4 5 6 7 8 # 20 15 12 21 24 28 32 36 96 35 10 37 17 Make a control chart for the daily number of visitors treated and plot the data on the control chart. Does the data indicate that the number visitors treated is "in Control"?
- where did you get 0.1235 from??Kobmison Crusoe spends 4 hours a day catching fish and picking coconuts. He can always cateh 2 umioer of coconuts he eats per day and Fis the number of ish he eats per day, How many fish will he choose to eat per day? F= 2LF or -2/.Wouldn't it be correct to say E=12, not 2E=12 for 12–(2/3)E=(1/3)E?
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