2. Consider the two cyclic molecules below A. В. a. The CH2 hydrogens of molecule A. and B. show very different acidities the pKa of A. is 16 while the pKa of B. is 36. Recall that the pKa is the negative log of the acid dissociation constant. First, draw the resulting conjugate base anions when one CH2 proton is removed from molecule A. and molecule B. Then, explain the differences in acidities by examining the relative stability of the two conjugate bases.

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2. Consider the two cyclic molecules below
А.
В.
a. The CH2 hydrogens of molecule A. and B. show very different acidities
the pka of A. is 16 while the pKa of B. is 36. Recall that the pKa is the
negative log of the acid dissociation constant. First, draw the resulting
conjugate base anions when one CH2 proton is removed from molecule A.
and molecule B. Then, explain the differences in acidities by examining the
relative stability of the two conjugate bases.
Transcribed Image Text:2. Consider the two cyclic molecules below А. В. a. The CH2 hydrogens of molecule A. and B. show very different acidities the pka of A. is 16 while the pKa of B. is 36. Recall that the pKa is the negative log of the acid dissociation constant. First, draw the resulting conjugate base anions when one CH2 proton is removed from molecule A. and molecule B. Then, explain the differences in acidities by examining the relative stability of the two conjugate bases.
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