2. A standard propane tank can hold about 17.0 L of propane. The 17.0 L of propane reacts with 76.2 L of oxygen, according to the reaction below. _C₂H₂ (g) + O₂(g) → CO₂ (g) + H₂O (g) a. Calculate the amount of carbon dioxide produced from the combustion reaction, in grams. (Hint: Determine the LR first) TURN OVER b. Calculate the amount of excess reactant left over, in liters (L).

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### Propane Combustion Problem for Educational Purposes

**Problem 2:**

A standard propane tank can hold about 17.0 L of propane. The 17.0 L of propane reacts with 76.2 L of oxygen, according to the reaction below.

\[\_ \, \text{C}_3 \text{H}_8 \, (\text{g}) + \_ \, \text{O}_2 \, (\text{g}) \rightarrow \_ \, \text{CO}_2 \, (\text{g}) + \_ \, \text{H}_2 \text{O} \, (\text{g})\]

**Tasks:**

a. Calculate the amount of carbon dioxide produced from the combustion reaction, in grams. (Hint: Determine the limiting reactant first)

**[ TURN OVER ]**

b. Calculate the amount of excess reactant left over, in liters (L).

---

#### Explanation:

In this problem, you are given the volumes of propane and oxygen available for a combustion reaction and are required to determine the amount of carbon dioxide produced and the excess reactant left over.

1. **Balanced Chemical Equation:**
   First, you need to write and balance the chemical equation for the combustion of propane (C3H8) with oxygen (O2).

2. **Calculate the Limiting Reactant (LR):**
   Next, using stoichiometry, identify the limiting reactant from the volumes given.

3. **Product Calculation:**
   Utilize the limiting reactant to calculate the volume and mass of carbon dioxide produced.

4. **Excess Reactant:**
   Determine how much of the excess reactant remains after the reaction.

This problem encourages practice with chemical stoichiometry and reaction balancing.
Transcribed Image Text:### Propane Combustion Problem for Educational Purposes **Problem 2:** A standard propane tank can hold about 17.0 L of propane. The 17.0 L of propane reacts with 76.2 L of oxygen, according to the reaction below. \[\_ \, \text{C}_3 \text{H}_8 \, (\text{g}) + \_ \, \text{O}_2 \, (\text{g}) \rightarrow \_ \, \text{CO}_2 \, (\text{g}) + \_ \, \text{H}_2 \text{O} \, (\text{g})\] **Tasks:** a. Calculate the amount of carbon dioxide produced from the combustion reaction, in grams. (Hint: Determine the limiting reactant first) **[ TURN OVER ]** b. Calculate the amount of excess reactant left over, in liters (L). --- #### Explanation: In this problem, you are given the volumes of propane and oxygen available for a combustion reaction and are required to determine the amount of carbon dioxide produced and the excess reactant left over. 1. **Balanced Chemical Equation:** First, you need to write and balance the chemical equation for the combustion of propane (C3H8) with oxygen (O2). 2. **Calculate the Limiting Reactant (LR):** Next, using stoichiometry, identify the limiting reactant from the volumes given. 3. **Product Calculation:** Utilize the limiting reactant to calculate the volume and mass of carbon dioxide produced. 4. **Excess Reactant:** Determine how much of the excess reactant remains after the reaction. This problem encourages practice with chemical stoichiometry and reaction balancing.
### How to Determine the Limiting Reactant (LR):

1. **Convert Reactant Quantities to Moles**
2. **Divide Each Mole Amount by Balanced Coefficients**
3. **Smallest Value = Limiting Reactant (LR)**

#### Additional Information:

- **Avogadro’s Number**: \( 6.023 \times 10^{23} \) molecules/1 mol
- **STP Volume**: 1 mol = 22.4 L
- **Leftover Calculation**: Leftover = Initial amount – Consumed amount

This guide outlines the necessary steps to determine the limiting reactant in a chemical reaction, converting quantities to moles, utilizing balanced chemical equations, and identifying the smallest resulting value as the limiting reactant. Key constants such as Avogadro's number and standard molar volume at standard temperature and pressure (STP) are also provided for reference.
Transcribed Image Text:### How to Determine the Limiting Reactant (LR): 1. **Convert Reactant Quantities to Moles** 2. **Divide Each Mole Amount by Balanced Coefficients** 3. **Smallest Value = Limiting Reactant (LR)** #### Additional Information: - **Avogadro’s Number**: \( 6.023 \times 10^{23} \) molecules/1 mol - **STP Volume**: 1 mol = 22.4 L - **Leftover Calculation**: Leftover = Initial amount – Consumed amount This guide outlines the necessary steps to determine the limiting reactant in a chemical reaction, converting quantities to moles, utilizing balanced chemical equations, and identifying the smallest resulting value as the limiting reactant. Key constants such as Avogadro's number and standard molar volume at standard temperature and pressure (STP) are also provided for reference.
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