2. A polarized dipole is at rest in an electric field of strength E = 1.78 x 105 N/C as shown. The dipole consists of two particles of charge Q = 51.9 mC and q = 18.7 mC and mass M = 222 µg. The massless rod that connects the particles has length e = 55.1 um. The dipole will rotate about its center of mass in the electric field, so if the initial angle shown is 0 = 31.2°, then what is the initial angular acceleration of the dipole? %3D 19.4 mg and m =
2. A polarized dipole is at rest in an electric field of strength E = 1.78 x 105 N/C as shown. The dipole consists of two particles of charge Q = 51.9 mC and q = 18.7 mC and mass M = 222 µg. The massless rod that connects the particles has length e = 55.1 um. The dipole will rotate about its center of mass in the electric field, so if the initial angle shown is 0 = 31.2°, then what is the initial angular acceleration of the dipole? %3D 19.4 mg and m =
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![2. A polarized dipole is at rest in an electric field of strength E = 1.78 × 105 N/C as shown. The dipole
consists of two particles of charge Q = 51.9 mC and q = 18.7 mC and mass M = 19.4 mg and m =
222 µg. The massless rod that connects the particles has length e = 55.1 um. The dipole will rotate
about its center of mass in the electric field, so if the initial angle shown is 0 = 31.2°, then what is the
initial angular acceleration of the dipole?
W](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc92ce40-641a-4d5c-b54e-ebe730dd3b9e%2F58c83dd9-8d2b-4a77-8878-77b3edfda526%2F49s6jhp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. A polarized dipole is at rest in an electric field of strength E = 1.78 × 105 N/C as shown. The dipole
consists of two particles of charge Q = 51.9 mC and q = 18.7 mC and mass M = 19.4 mg and m =
222 µg. The massless rod that connects the particles has length e = 55.1 um. The dipole will rotate
about its center of mass in the electric field, so if the initial angle shown is 0 = 31.2°, then what is the
initial angular acceleration of the dipole?
W
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