A charged particle of mass m =length { = 25.5 cm and spun in circular motion with w = 7.85 rad/s. At the moment shown thecharged particle is passing through an electric field of strength E = 3.91 × 105 N/C that is angledabove the horizontal direction at an angle of o = 18.3°.57.2 g and charge q = +2.14 µC is attached to a massless string ofm, q2.Using the same values of angular velocity, electric field strength, particlecharge, particle mass and string length, what angle would the electric field need inorder for the string to be at an angle of 1.00° with the vertical?

Given that mass m=57.2 g charge q=+2.14μC length of string l=25.5 cm angular velocity ω=7.85rad/s…

A charged particle of mass m = 57.2 g and charge q = +2.14 µC is attached to a massless string of length l = 25.5 cm and spun in circular motion with w = 7.85 rad/s. At the moment shown the charged particle is passing through an electric field of strength E = 3.91 × 105 N/C that is angled above the horizontal direction at an angle of o = 18.3°.

A charged particle of mass m = 57.2 g and charge q = +2.14 µC is attached to a massless string of length l = 25.5 cm and spun in circular motion with w = 7.85 rad/s. At the moment shown the charged particle is passing through an electric field of strength E = 3.91 × 105 N/C that is angled above the horizontal direction at an angle of o = 18.3°.