2) Un-competitive inhibition in a single substrate (S) enzyme-catalyzed reaction: In uncompetitive inhibition, the inhibitor (I) can only bind to the enzyme-substrate complex (so the Enzyme-Inhibitor complex El does not occur). Apply a quasi-steady-state analysis to verify that uncompetitive inhibition reduces Kм and Vmax by the same factor. k₁ k2 S+E ES + k_1 k3 I+ ES ESI k-3 Hint: Apparent Kм = KM 1+[I]/K₁' Vmax Apparent Vmax = 1+[I]/Ki E+P

Managerial Economics: Applications, Strategies and Tactics (MindTap Course List)
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Author:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
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ChapterB: Differential Calculus Techniques In Management
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2) Un-competitive inhibition in a single substrate (S) enzyme-catalyzed reaction:
In uncompetitive inhibition, the inhibitor (I) can only bind to the enzyme-substrate complex (so
the Enzyme-Inhibitor complex El does not occur). Apply a quasi-steady-state analysis to verify
that uncompetitive inhibition reduces Kм and Vmax by the same factor.
k₁
k2
S+E
ES
+
k_1
k3
I+ ES
ESI
k-3
Hint: Apparent Kм
=
KM
1+[I]/K₁'
Vmax
Apparent Vmax
=
1+[I]/Ki
E+P
Transcribed Image Text:2) Un-competitive inhibition in a single substrate (S) enzyme-catalyzed reaction: In uncompetitive inhibition, the inhibitor (I) can only bind to the enzyme-substrate complex (so the Enzyme-Inhibitor complex El does not occur). Apply a quasi-steady-state analysis to verify that uncompetitive inhibition reduces Kм and Vmax by the same factor. k₁ k2 S+E ES + k_1 k3 I+ ES ESI k-3 Hint: Apparent Kм = KM 1+[I]/K₁' Vmax Apparent Vmax = 1+[I]/Ki E+P
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