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- Hi in the below code I would like to remove the blank tokens and how to achieve it. #include <stdio.h> #include <string.h> #include <stdlib.h> int count_tokens(const char* str) { int count = 0; int invalidToken = 0; // set false for(int i = 0; i <= strlen(str); i++) { if( i == strlen(str) || str[i] == 32){ // if past end of string, or if space if(invalidToken) { invalidToken = 0; // set false continue; } else { count++; // increment count only if token was not invalid continue; } } if( !(str[i] >= 97 && str[i] <= 122) ) { // if not lowercase letter invalidToken = 1; // set true } } return count; } char** split_tokens(const char* str) { char **tokenArr; tokenArr = (char **) malloc(count_tokens(str) * sizeof(char*)); /*use count_tokes() to determine the length*/ int…Can someone help me answer this question?#include <iostream>using namespace std; char* duplicateWithoutBlanks(char *word){int len = sizeof(word); char *new_str = new char[len + 1]; int k = 0; for (int i = 0; i < len; ++i){if (word[i] != ' ')new_str[k++] = word[i];} new_str[k] = '\0'; return new_str;} int main(){// Testing code char word[] = "Hello, World!"; char* result = duplicateWithoutBlanks(word); cout<< "word: "<< word<< "\nResult: "<< result; ; return 0;} What to change to out put the same word without blank?
- Lab 0(L): I Can, Therefore I MustJUnit: P2J12Test.javaA jovial old grandpa mathematician straight out of central casting often appearing in Numberphilevideos, Neil Sloane is behind the Online Encyclopedia of Integer Sequences, a wonderful tool forcombinatorial explorations. This lab has you implement two methods to generate elements of twointeresting integer sequences whose chaotic behaviour emerges from iteration of a deceptivelysimple rule. Both sequences are filled in ascending order in a greedy fashion, so that each elementis always the smallest number that avoids creating a conflict with the previously generatedelements in the sequence.Note that being defined by mathematicians, these sequences start from the position one instead ofthe position zero, the way how sequences work for us budding computer scientists who have toactually get our hands dirty and therefore prefer zero-based indexing. When asked to produce thefirst n elements of the sequence, these methods should create an…2184=9100(.03*t)Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = NUM_VALS - 1. Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]). Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() { const int NUM_VALS = 4; int courseGrades[NUM_VALS]; int i; for (i = 0; i < NUM_VALS; ++i) { cin >> courseGrades[i]; } /* Your solution goes…
- Can you fix this please? with 5 53 5099 1223 567 17 4 1871 8069 3581 6841 #include <iostream>using namespace std; const int SORT_MAX_SIZE = 8; bool IsPrimeRecur(int dividend, int divisor) { if (divisor == 1) { return true; } if (dividend % divisor == 0) { return false; } return IsPrimeRecur(dividend, divisor-1);} bool IsArrayPrimeRecur(int arr[], int size, int index) { cout << "Entering IsArrayPrimeRecur" << endl; if (index == size) { cout << "Leaving IsArrayPrimeRecur" << endl; return true; } if (!IsPrimeRecur(arr[index], arr[index]-1)) { cout << "Leaving IsArrayPrimeRecur" << endl; return false; } return IsArrayPrimeRecur(arr, size, index+1);} bool IsArrayPrimeIter(int arr[], int size) { cout << "Entering IsArrayPrimeIter" << endl; for (int i = 0; i < size; i++) { for (int j = 2; j < arr[i]; j++) { if (arr[i] % j == 0) {…Please don’t use chegg C++ programming You are playing a mobile game with circular balls. At the beginning, you are given an string representing an array of integers where every element represents radius of the circle. At every stage, you need to pick the two largest circles and merge them together according to following set of rules: 1)If r1 == r2, both circles are vanished 2) If r1 != r2, find abs(r1 - r2) as new radius and replace it higher radius circle and then remove the other circle. At the end of the game, there will be at most one circle left. If there are no circle left, return 0. Otherwise return the radius of the last circle. You MUST use a Priority Queue implementation to receive credit. You may NOT use STL to implement the Priority Queue directly, however you are allowed to use vectors and such. Case 1:Input 1: 3 3 Output 1: 0 Case 2:Input 2: 1 2 3 1 Output 2: 1 Case 3:Input 3: 30 80 50 10 90 20 50Output 3: 10text file 80 1 2 3 100 100 100 1001 0 2 100 3 4 100 1002 2 0 4 4 100 5 1003 100 4 0 100 100 4 100100 3 4 100 0 3 3 3100 4 100 100 3 0 100 1100 100 5 4 3 100 0 2100 100 100 100 3 1 2 0 My code below. I am getting an error when trying to create my adjacency matrix. i dont know what i am doing wrong def readMatrix(inputfilename): ''' Returns a two-dimentional array created from the data in the given file. Pre: 'inputfilename' is the name of a text file whose first row contains the number of vertices in a graph and whose subsequent rows contain the rows of the adjacency matrix of the graph. ''' # Open the file f = open(inputfilename, 'r') # Read the number of vertices from the first line of the file n = int(f.readline().strip()) # Read the rest of the file stripping off the newline characters and splitting it into # a list of intger values rest = f.read().strip().split() # Create the adjacency matrix adjMat = []…
- JAVA PROGRAM PLEASE MODIFY THIS PROGRAM SO WHEN I UPLOAD IT TO HYPERGRADE IT PASSES ALL TEST CASES. BECAUSE IT DOES NOT PASS ALL THE TEXT CASES. IT ONLY PASSES 8 PUT OF 16 TEXT CASES. ALL LENGHTS, HEIGHS AND ARRAY ELEMENTS ARE IN THREE DIGITS AFTER THE DEICIMAL POINT. ALSO, WHEN YOU TYPE BADFILE.TXT IT SHOULD SAY AFER THAT Please enter the file name AGAIN or type QUIT to exit:\n THEN YOU TYPE IN THE FILE NAME. I PROVIDED SCREENSHOTS OF THE FAILED TEST CASES.AND THE INPUTS. import java.io.*;import java.util.*;public class ArrayListOperations { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); while(true) { System.out.print("Please enter the file name or type QUIT to exit:\n"); String filename = scanner.nextLine(); if(filename.equalsIgnoreCase("QUIT")) { break; } File file = new File(filename); if(!file.exists()) {…Question 16 Rk Full explain this question very fast solution sent meQuestion 1: Magic Matrix Magic square is an ? × ? matrix that is filled with the numbers 1,2,3, . . . . . , ?2 is a magic square if the sum of the elements in each row, in each column, and in the two diagonals is the same value. 6 1 8 7 5 3 2 9 4 Write a Java code to randomly generate a 3X3 matrix and check if the matrix is the magic square. In your code you must test two features: a. Does each of the numbers 1,2,3,….9 occur in the matrix? b. Are the sums of the rows, columns, and diagonals equal to each other? Note: to generate a random number use the method Math.random() which generates a pseudo random number greater than or equal to 0 and less than 1. Sample Output could be as follows: Sample 1: The randomly generated matrix is: 4 3 8 9 5 1 2 7 6 Sample 2: The randomly generated matrix is: 4 9 2 3 5 7 8 1 6
