2 m= 1 kg Process path (straight line) 1 R= 0.50 2 Cy = 0.5 kJ/kg K V= 1 m3 P= 300 kPa V= 0.5 m3 P= 600 kPa An ideal gas in a piston undergoes a process from state 1 to state 2 above. d) The work to move the piston is: a) performed ON the system (Win) b) performed BY the system (Wout) e) If no other work is done on or by the system during the process, circle the term that must be non-zero (i.e. what else occurs during the process) to satisfy the Conservation of Energy Equation for a closed system having no change in KE or PE. Win - Wout + Qin - Qout - Δυ llo,

2 m= 1 kg Process path (straight line) 1 R= 0.50 2 Cy = 0.5 kJ/kg K V= 1 m3 P= 300 kPa V= 0.5 m3 P= 600 kPa An ideal gas in a piston undergoes a process from state 1 to state 2 above. d) The work to move the piston is: a) performed ON the system (Win) b) performed BY the system (Wout) e) If no other work is done on or by the system during the process, circle the term that must be non-zero (i.e. what else occurs during the process) to satisfy the Conservation of Energy Equation for a closed system having no change in KE or PE. Win - Wout + Qin - Qout - Δυ llo,

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

m= 1 kg
Process path
(straight line)
R= 0.50
2
C, = 0.5 kJ/kg K
P
V= 1 m3
P= 300 kPa
V= 0.5 m3
P= 600 kPa
An ideal gas in a piston undergoes a process from state 1 to state 2 above.
d) The work to move the piston is: a) performed ON the system (Win) b) performed BY the
system (Wout)
e) If no other work is done on or by the system during the process, circle the term that must
be non-zero (i.e. what else occurs during the process) to satisfy the Conservation of
Energy Equation for a closed system having no change in KE or PE.
W - W,
+ Qin - Qout
= AU
in
out

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