Water atp1= 5 bars andT1= 240◦C is inside a rigid closed container of volumeV= 0.5 m3, which experiences a heat loss, so that the water inside the container reaches afinal state given by a mixture of liquid and vapor at T2= 20◦C. Determine:a) The final pressure,p2, in barsb) The final quality,x2c) The final mass of liquid, in kgd) The amount of heat removed, in kJ
Water atp1= 5 bars andT1= 240◦C is inside a rigid closed container of volumeV= 0.5 m3, which experiences a heat loss, so that the water inside the container reaches afinal state given by a mixture of liquid and vapor at T2= 20◦C.
Determine:a) The final pressure,p2, in barsb) The final quality,x2c) The final mass of liquid, in kgd) The amount of heat removed, in kJ
Since we only answer upto three subparts, we will answer the first three. Please resubmit the question and specify other subparts you would like answered.
(a)
Write the specific volume of the water for the initial condition from the steam table corresponding to 5 bar and 240oC.
Here, v1 is the specific volume of the water at the initial condition.
Since the water inside the container finally is in a state of mixture of both vapor and liquid at 20oC.
Write the properties of water at 20oC from the saturated steam table.
Here, Psat is the saturation pressure of water at 20oC, vg is the specific volume of water vapor at 20oC, and vf is the specific volume of liquid water at 20oC.
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