2 i) int x = 1; int y //L1 %3D 2; 3; //L2 //L3 //L4 %3D int z y; %3D //L5 //L6 //L7 x + 5; = z; System.out.println(x + "+" + z + "-" + y); N
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A: I HAVE PROVIDED SOLUTION IN STEP2
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Explain in your own words what the code in 2i does step by step
Step by step
Solved in 2 steps
- int x; X=-2; do { x++; cout0); cout<<"done"; O done O -2 done O -1 done#include using namespace std; int main() int x=1,y=2; for (int i=0; i<3; i++) e{ x=x*y; 8{ } cout<int main() int i = 3, * j, k; j = &i; k = i; "j= 10; cout << i * *j * i + *j*k; return 0; O 30 3 O 20 20 O 10 20 O 10 30int y=0,i; for (int i=0;i<10;++i) y+=i; 36 66 45 55int calculatepower (int x, int y){ if (y > 0) return x* else return 1; int main (){ int num, pwr; cout > num; cout > pwr; cout <« "Number "<#include using namespace std; int main () int x, y; { X = 5; y = ++x cout << x << y; %3D ++x; %3D x = 5; y = x++ * ++x; cout << x < y; return e; } 525636 747953 749735 636636be recor #include #include minutes #include limit on int func(int, int, int, int); main(){ srand(time(NULL)); int a, b, c, fNum; printf("Choose three different numbers between 0-39:"); scanf ("%d%d%d", &a, &b, &c); fNum = func (a, b, c, 25); printf("\nThe result: %d", fNum); } int func (int ul, int u2, int u3, int iter){ srand (time (NULL)); int n1=0, i=0, count=0; for (;ivoid funOne(int a, int& b, char v); void main() { int num1=10; char ch='A'; funOne(num1, 15,ch)<Number of digits int main() {int c=0;int i=3856; int l=i; while(l>0) {l=l/10; c++; } printf("%d",c); return 0; } Summation of digits int main() {int sum=0; int i=384; int l=i; while(l>0) { sum+=l%10; l=l/10;} printf("%d",sum); return 0; }10. a. Point Out errors: #include void main() { char arr[8]="Rhombus"; int i; for(i=0;i #include void main() { char *str1="United"; char *str2="Front"; char *str3; str3=strcat(str1,str2); printf("\n %s",str3); [- [- c. Compare Union and Structure.2 ii) String character = "Leia"; String planet //L1 = "Alderaan"; //L2 if (character.equals ("Rey")) { planet } //L3 = "Hoth"; //L4 else { planet } "Jakku"; //L5 + planet); //L6 %3D %3D System.out.println(character + at Answer to question 2 ii): Complete the dry run table (you may not need all rows): : LINE character planet character.equals(“Rey")? print Options -int i,j; for(i=1;ii;--j) cout<<"-"; } **_* **_** ***SEE MORE QUESTIONSRecommended textbooks for youC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage LearningC++ Programming: From Problem Analysis to Program…Computer ScienceISBN:9781337102087Author:D. S. MalikPublisher:Cengage Learning