int sum =int i = 0;while (i < 4){sum = sum + i;%3D%3D{ '++!System.out.print(sum);What is the value of sum?a. 6Ob. 10C. 15Od. 21

Given Program: class HelloWorld { public static void main(String[] args) { int sum=0;…

Answered: int sum = 0; int i = 0; while (i < 4)…

Engineering

Computer Science

int sum = 0; int i = 0; while (i < 4) {sum = sum + i; i++; } %3D %3D

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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PLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…
int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;
int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…
int getUpperScore(){ int upperScore = 0; for(int i = ONES; i <= SIXES; i++){ upperScore += score[i]; } return upperScore + getBonusScore(); } //Returns the score of the upper part of the board int getLowerScore(){ int lowerScore = 0; for(int i = THREE_OF_KIND; i <= YAHTZEE; i++){ lowerScore += score[i]; } return lowerScore; } //Returns the bonus points int getBonusScore(){ const int UPPER_SCORES_THRESHOLD = 63; const int BONUS_POINTS = 35; if(getUpperScore() >= UPPER_SCORES_THRESHOLD){ return BONUS_POINTS; } return 0; } //Returns the total score int getTotalScore(){ return getUpperScore() + getLowerScore(); } Test 10: Check upper board and having bonus correctly (0/3) failed
function myChoice(items) {if (!this.value && !this.items) {this.items = items[0];} else if (!this.value || (params.length > 0 && params[0] == "rechoose")) {let index = Math.floor(Math.random() * (this.items.length - 0)) + 0;this.value = this.items[index];return this.value;}return this.value;} var a = myChoice([1, "a", 3, false]);console.log(myChoice(3, 12));console.log(myChoice(51, -2));console.log(myChoice("happy", false));console.log(myChoice([1, 2, 3]));console.log(myChoice("rechoose"));console.log(myChoice(a, a)); these are directions and examples myChoice( items ) This function accepts a list of items as input and creates a function that returns a randomly-chosen item. After choosing a random item, that same item will be always be returned, regardless of the functions input, with one exception. If the first input is the string 'rechoose', then a new random item will be chosen and therafter returned. this is KEYYYY!! Examples var a = myChoice( [1, "a", 3, false]…
#include tinclude 3 tinclude 4 void modify(int *, int) ; 5 int main (void) int sensor[15]; int i, thr = 15; for (i=0;i<15;i++) * (sensor+i)=rand () *100; 8 10 11 printf("Sensor Value\n"); for (i=0;i<15;i++) printf("%3d",* (sensor+i)); modify(sensor,thr); printf("\nAfter Modification\n"); for (i=0;i<15;i++) printf("%3d",*(sensor+i)); return 0; 13 14 15 16 17 18 19 20 L} 21 22 void modify(int *d, int t) 23B { 24 int i; for (i=0;i<15;i++) 25 26 if (*(d+i) <= t) * (d+i) = t; 27 28 29 30 B Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification 41 67 34 12 69 24 78 58 62 64 12 45 81 27 61 41 67 34 20 69 24 78 58 62 64 25 45 81 27 61 D Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification 41 67 34 15 69 24 78 58 62 64 15 45 81 27 61 61 87 54 20 89 44 98 78 82 84 25 65101 47 81 oao 123 456 r89
Number of digits int main() {int c=0;int i=3856; int l=i; while(l>0) {l=l/10; c++; } printf("%d",c); return 0; } Summation of digits int main() {int sum=0; int i=384; int l=i; while(l>0) { sum+=l%10; l=l/10;} printf("%d",sum); return 0; }
В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }
%3D 0 = uns ju! int i = 0; while (i < 4) {sum = sum + i; { '++! System.out.print(i); what is the value of i ? Ob. 5 C. 4
debug
Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
struct ID { int x; int y; }; struct name { ID r; }; int main() { name a[2]; for (int i=0;i<2;i++) { a[i).r.x=i; a[i].r.y=i+1; } for(int i=0;i<2;i++) cout<