2+ d. 4H3O+ (aq) + 2Cl¯ (aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (g) 2+ [Mn²+ ] [C1₂] [H₂O+]*[C1-1² 2+ Mn²+ [H₂O][C1₂] O Ke Kc = Oke = [H3O+][CI]²[MnO₂] [Mn²+ ] [H₂O] [C1₂] [H3O+]*[C1-1² [MnO₂] H₂
2+ d. 4H3O+ (aq) + 2Cl¯ (aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (g) 2+ [Mn²+ ] [C1₂] [H₂O+]*[C1-1² 2+ Mn²+ [H₂O][C1₂] O Ke Kc = Oke = [H3O+][CI]²[MnO₂] [Mn²+ ] [H₂O] [C1₂] [H3O+]*[C1-1² [MnO₂] H₂
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![2+
d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9)
Oke
O Ke
=
=
O Ke =
2+
[Mn²+ ][C1₂]
[H3O+] * [CI-1²
[Mn²+][H₂O][C1₂]
2+
[H³O+][CI¯]²[MnO₂2]
[Mn²+ ] [H₂O1] [C1₂]
2+
[H3O+] * [CI-1²[MnO₂]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff2d324e2-7a67-4e3d-bb22-9ad23fbeb72b%2Fe9d17a2d-bf45-488e-99e8-2efe4584c205%2F0u6dum_processed.png&w=3840&q=75)
Transcribed Image Text:2+
d. 4H3O+ (aq) + 2Cl(aq) + MnO₂ (s) ⇒ Mn²+ (aq) + 6H₂O(1) + Cl₂ (9)
Oke
O Ke
=
=
O Ke =
2+
[Mn²+ ][C1₂]
[H3O+] * [CI-1²
[Mn²+][H₂O][C1₂]
2+
[H³O+][CI¯]²[MnO₂2]
[Mn²+ ] [H₂O1] [C1₂]
2+
[H3O+] * [CI-1²[MnO₂]
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