TI Pt Cr3+ (1 M) Cr2+ (1 M) T13+ (1 M) T13+ (aq) + 3e- TI (s) Cr2+ (aq) → Cr3+ (aq) + e- The species being oxidized is and the species being reduced is respectively. Note: "TI" is the symbol for thallium (element #81). Pt/ TI O T / Cr2* O Cr/T O Cr/TI • TI/ Cr

TI Pt Cr3+ (1 M) Cr2+ (1 M) T13+ (1 M) T13+ (aq) + 3e- TI (s) Cr2+ (aq) → Cr3+ (aq) + e- The species being oxidized is and the species being reduced is respectively. Note: "TI" is the symbol for thallium (element #81). Pt/ TI O T / Cr2* O Cr/T O Cr/TI • TI/ Cr

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

+1.14 V
TI
Pt
Cr3+ (1 M)
Cr2+ (1 M)
T13+ (1 M)
T13+ (aq) + 3e- TI (s)
Cr2+ (aq) → Cr3+ (aq) + e-
The species being oxidized is
and the species being reduced is
respectively.
Note: "TI" is the symbol for thallium (element #81).
O Pt / TI
O TI3 / Cr2+
O C/TP
O C+/ TI
• TI/ Cr+
DELL
Esc
F1
F2
F3
F4
F5
F6
F7
F8
F9
%23

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