- Write the chemical equation(s) for each part of the experiment, as outlined in Equation 1. (0) Part I Cuole)de.I (a) Part I (b) Part II Cu(s) (Cu(H,O),* (aq) Cu(OH),(s) CuO(s) (d) Part IV (e) Part V (Cu(H,O),* (aq) Cu(s) dihoeuls vile

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ford
VOL
3. Write the chemical equation(s) for each part of the experiment, as outlined in Equation 1.
(a) Part I
Cu(s)
(Cu(H,O),* (aq)
12+
(b) Part II
(c) Part III
Cu(OH),(s)
CuO(s)
(d) Part IV
[Cu(H,O),* (aq)
12+
(e) Part V
Cu(s)
bodl amul s i OVH diw lo noitsbixo art tuo yuso teurm uoy dw
a Ternary Mixture
Transcribed Image Text:Ford VOL 3. Write the chemical equation(s) for each part of the experiment, as outlined in Equation 1. (a) Part I Cu(s) (Cu(H,O),* (aq) 12+ (b) Part II (c) Part III Cu(OH),(s) CuO(s) (d) Part IV [Cu(H,O),* (aq) 12+ (e) Part V Cu(s) bodl amul s i OVH diw lo noitsbixo art tuo yuso teurm uoy dw a Ternary Mixture
Expert Solution
Step 1

(a)

Chemistry homework question answer, step 1, image 1This reaction actually occurs in 2 steps. In the first step, the copper (red-brown)

is oxidized to copper(II) ions by nitrate ions that the addition of nitric acid (HNO3)

suppliesAt the same time, the Nitrate ions (NO3-) are reduced to nitrogen(IV) oxide

(NO2), a brown gas. When all of the copper has been oxidized we perform the second

step by diluting the reaction mixture (RM) with water. The addition of H2O produces

hexaaquocopper(II) ions, [Cu(H2O)6]2+, a blue solution.

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