(2) Consider a container surrounded by adiabatic walls. The container is separated by a fixed and heat-conductive wall into two compartments Vi and V2. Using the condition to maximize entropy, show that the temperatures inside the two compartments are equal when the equilibrium is reached. Show this with and without using Lagrange multiplier.
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- Pressure is applied isothermally to a container that holds a liquid. Assuming the liquid is compressible, what has happened to the entropy? The entropy has decreased because the applied pressure results in the particles being less free to move, making their positions more predictable. The entropy has increased because the applied pressure results in heat being transferred from the environment to the system. The entropy has increased because the particles move more rapidly at higher pressure, making their velocities less predictable. None of the above.A 2.00-mol sample of H2 gas is contained in the left side of the container shown below, which has equal volumes on the left and right. The right side is evacuated. When the valve is opened, the gas streams into the right side. (a) What is the entropy change of the gas? (b) Does the temperature of the gas change? Assume the container is so large that the hydrogen behaves as an ideal gas. (Wouldn't the temperature decrease because the temperature in a vacuum would be really cold?)Calculate the efficiency of the reversible cycle in figure for an ideal monoatomic gas where the transformation from 1->2 is described by the equation P2 V = A= constant (Assume V2 = 4 V1). P 3 1 V1 2 V2 V Hint: You might need to use the following integral: = √ + GA little bit of a problem can be found for Q1-2 = AU + W where the integral above may result useful to know.
- Prove that entropy change from state A to state B is the same for both paths as shown in the TV diagram in the case of an ideal gas: 1. An adiabatic reversible expansion from point A (P1, V1, T1) to point B (P2, V2, T2) 2. An isobaric reversible process from A (P1, V1, T1) to C then followed by an isothermal reversible process from C to B (P2, V2, T2) P1, V1, T1 A Adiabatic Isobaric B P2, V2, T2 Isothermal C VTwo moles of an ideal gas undergo an irreversible isothermal expansion fromVa=100 liters to Vb=300 liters at T=300K.(a) What is the entropy change for this process?(b) What is the Gibbs free energy change?(c) Is this process spontaneous or not? Explain your answer.What is the entropy change for 3.20 mol of an ideal monatomic gas undergoing a reversible increase in temperature from 380 K to 425 K at constant volume?
- When a metal bar is temporarily connected between a hot reservoir at Th and a cold reservoir at Tc, the energy transferred by heat from the hot reservoir to the cold reservoir is Qh. In this irreversible process, find expressions for the change in entropy of the following. (Use any variable or symbol stated above as necessary.) (a) the hot reservoir ΔSh = (b) the cold reservoir ΔSc = (c) the Universe ΔSU =Polymers, like rubber, are made of very long molecules, usually tangled up in a configuration that has lots of entropy. As a very crude model of a rubber band, consider a chain of N links, each of length L Imagine that each link has only two possible states, pointing either left or right. The total length L of the rubber band is the net displacement from the beginning of the first link to the end of the last link. Using the thermodynamic identity, you can now express the tension force F in terms of a partial derivative of the entropy. From this expression, compute the tension in terms of L, T , N, and l.Consider the adiabatic free expansion of n moles of an ideal gas from volume V₁ to volume V2, where V₂ > V₁. [Hint: check lecture 19, chapter 5.6, process number 5. Note that such a process happens quasi-instantaneously, thus, it is irreversible.] (1) Calculate the change in entropy of the gas. (2) Calculate the change in entropy of the environment. (3) Evaluate the total change in entropy (AS = ASgas + ASenv.) for 1 mole, with V₂ = 2V/₁.